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3 years ago

Which of the following statements about energy in systems is true?

1 answer:

Elena-2011 [213]3 years ago

8 0

Option number three is correct energy can be transformed and moved and released but it can't be destroyed and doesn't disappear.

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A person's center of mass is easily found by having the person lie on a reaction board. A horizontal, 2.1-m-long, 6.6 kg reactio

MrRissso [65]

Answer is x hopefully this helps your stupid head

5 0

3 years ago

Radio wave radiation falls in the wavelength region of 10.0 to 1000 meters. What is the energy of radio wave radiation that has

dmitriy555 [2]

Answer:

Explanation:

Given

Wavelength of radiation $\lambda =784\ m$

We know Energy of wave with wavelength $\lambda$ is given by

$E=\frac{hc}{\lambda }$

where h=Planck's constant

c=velocity of light

$\lambda$ =wavelength of wave

$E=\frac{6.626\times 10^{-34}\times 3\times 10^8}{784}$

$E=2.53\times 10^{-28}\ J$

Hence the energy of the wave with wavelength 784 m is $2.53\times 10^{-28}\ J$

7 0

3 years ago

A flea jumps straight up to a maximum height of 0.400 m . what is its initial velocity v0 as it leaves the ground?

timama [110]

For an object`s motion, the Kinematic equation is,

$v^2=v_{0}^2+2ah$

Here, v is the final velocity and h is stands for the height of the object and a is the acceleration of the object.

As according to question,

$v=0m/s,a=g-9.8 m/s^2$ and $h = 0.400 m$

Thus, putting these values in above equation, we get

$0= v_{0}^2 -2gh$

$v_{0} =\sqrt{2 \times 9.8 \times 0.400 }$

$v_{0} = 2.8 m/s$

Therefore, initial velocity is 2.8 m/s

8 0

3 years ago

If the mass is displaced 0.270 m from equilibrium and released, what is its speed when it is 0.130 m from equilibrium?

puteri [66]

Answer:

The speed is 1.52 m.

Explanation:

Given that,

Displacement =0.270 m

Distance = 0.130 m

Suppose a 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m.

We need to calculate the angular velocity

Using formula of angular velocity

$\omega=\sqrt{\dfrac{k}{m}}$

Put the value into the formula

$\omega=\sqrt{\dfrac{13.3}{0.321}}$

$\omega=6.43\ rad/s$

We need to calculate the velocity

Using formula of velocity

$v=\omega\sqrt{A^2-x^2}$

Put the value into the formula

$v=6.43\times\sqrt{0.270^2-0.130^2}$

$v=1.52\ m/s$

Hence, The speed is 1.52 m.

6 0

2 years ago

Which characteristic should a good scientific question have?

RUDIKE [14]

A good scientific question should be pre-determined and also have a meaning or relation to science.

7 0

3 years ago

Read 2 more answers