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Elan Coil [88]
3 years ago
7

Which statement best describes the weather shown by the purple combination of semicircles and triangles on a line on a weather m

ap?
An occluded front can cause light to heavy precipitation that may last several days.

A cold front can cause heavy rain, thunder, and lightning.

A stationary front may produce rainy or snowy weather for several days.

A warm front brings drizzly weather.
Physics
2 answers:
Vaselesa [24]3 years ago
8 0

Answer:

D) A warm front brings drizzly weather.

Explanation:

Radda [10]3 years ago
8 0

Answer:D is the answer

Explanation:hope it helps!

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1. Is the relationship between velocity and centripetal force a direct, linear relationship or is it a nonlinear square relation
Svetllana [295]

Answer:

non linear square relationship

Explanation:

formula for centripetal force is given as

a = mv^2/r

here a ic centripetal acceleration , m is mass of body moving in circle of radius r and v is velocity of body . If m ,and r are constant we have

a = constant × v^2

a α v^2

hence non linear square relationship

7 0
3 years ago
I am starting a PowerPoint presentation about Cat-Eye Syndrome. I don't know how to start my sentence. How can I start?
ioda

Answer:

first introduce what is cat-eye syndrome e.g cat eye syndrome is....

then write about the causes and symptoms of cat eye syndrome

8 0
3 years ago
Ammonia enters the expansion valve of a refrigeration system at a pressure of 10 bar and a temperature of 22oC and exits at 2.0
KonstantinChe [14]

Answer:

The  the quality of the refrigerant at the exit of the expansion valve is 0.179.

Explanation:

Given that,

Initial pressure = 10 bar

Temperature = 22°C

Final pressure = 2.0 bar

We using the value of h

h = 293.4\ kJ/kg

The refrigerant during expansion undergoes a throttling process

Therefore, h_{1}=h_{2}

We need to calculate the quality of the refrigerant at the exit of the expansion valve

At 2.0 bar,

The property of ammonia

h_{f}=47.8 kJ/kg

h_{g}=1417.7 kJ/kg

Using formula

h_{2}=h_{f}+x(h_{g}-h_{f})

Put the value into the formula

293.4 =47.8+x(1417.7-47.8)

x=\dfrac{293.4-47.8}{1417.7-47.8}

x=0.179

Hence, The  the quality of the refrigerant at the exit of the expansion valve is 0.179.

6 0
3 years ago
A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k
Bad White [126]

Answer:

v_{f,w} = 1.791\,\frac{m}{s}, v_{f,c} = 0.972\,\frac{m}{s}

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}

The final angular speed is:

\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}

\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev}  \right)

\omega_{f} \approx 5.116\,\frac{rad}{s}

The tangential velocities of the wheel and the clay are, respectively:

v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )

v_{f,w} = 1.791\,\frac{m}{s}

v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )

v_{f,c} = 0.972\,\frac{m}{s}

5 0
3 years ago
Please help me. I don’t understand this.
guajiro [1.7K]

Answer:

Ft = 0[N]

Explanation:

To understand this problem we must perform an analysis of forces on the X axis, which coincides with the axis of forces of dogs.

In this way performing a sum of forces on the X-axis we will have (newton's third law):

F_{rigth}-F_{left}+F_{total} =0\\\  200-200+F_{total} =0\\F_{total}=0

From this analysis we can see that the resulting or total force is equal to zero, since there is no movement.

8 0
4 years ago
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