All categories

4 months ago

RT and UW are parallel lines

Mathematics

1 answer:

Veseljchak [2.6K]4 months ago

5 0

Answer: ∡RSQ and ∡TSQ

Supplementary angles are angles that add up to 180 degrees. We can see in the picture that both angles are located on the same line, and no other angles are involved, so they must equal 180.

We can also use the process of elimination:

∡RSQ and ∡UVS are congruent because they are consecutive angles.

∡RSQ and ∡WVX are also congruent because they are alternate exterior angles.
∡RSQ and ∡TSV are also congruent because they are vertical angles.

You might be interested in

Figure ABCD is a parallelogram. What is the value of x? A B O 6 ET O 7 8 5x + 3 38 09 D С

kondor19780726 [428]

Answer:

Given: It is given that and .

To Prove: ABCD is a parallelogram.

Statements

1. and

Reason: Given

2. are alternate interior angles

Reason: Def of alternate interior angles

Reason: Alternate interior angles are congruent

Reason: Reflexive property

Reason: SAS congruency theorem

Reason: Corresponding Parts of Congruent triangles are Congruent (CPCTC)

7. ABCD is a parallelogram

Reason: Parallelogram Side Theorem

Step-by-step explanation:

please mark me brainliest

6 0

1 year ago

Hey! i’ll give brainliest please help

gizmo_the_mogwai [7]

A women doesn’t feel right about ditching school is an internal struggle

3 0

2 years ago

17X+1 +20x-14 = 90 find x

professor190 [17]

Answer:

x = 2.8

Step-by-step explanation:

17x+1+20x-14 = 90

Combine like terms.

37x-13 = 90

Add 13 on both sides.

37x-13 = 90

+13 +13

37x = 103

Divide both sides by 37.

37x = 103

/37 /37

x = 2.8

(I rounded up, but if you need a more specific number, just search up 103 divided by 37.)

Hopefully this helps you!! Have an amazing day c:

7 0

2 years ago

Brandon rode his bike 90% of the distance that Carlee did this week. He rode 58.5 miles. How many miles did Carlee ride?

Crank

Carlee rode 65 miles

7 0

2 years ago

Which ordered pair is a solution of linear equations?

Bingel [31]

Answer:

$\{\frac{2}{3}, \frac{1}{5}\}$

ordered pair is the Solution to the given System.

Step-by-step explanation:

Given:

$\frac{1}{2}x- \frac{3}{4}y= \frac{11}{60} ...........Equation( 1 )\\ \\\frac{2}{5}x+ \frac{1}{6}y= \frac{3}{10} ...........Equation( 2 )\\$

To Check:

Which ordered pair is the Solution to the given System. ?

Solution:

If $\{\frac{2}{3}, \frac{1}{5}\}$

is the Solution then it must satisfy the given equation. i.e .Left Hand Side (L.H.S) must be Equal to Right Hand Side (R.H.S) of both the given equation for

$\{x=\frac{2}{3}, y=\frac{1}{5}\}$

∴ For Equation ( 1 )

$L.H.S=\frac{1}{2}\times \frac{2}{3}- \frac{3}{4}\times \frac{1}{5}\\\\\\=\frac{1}{3} -\frac{3}{20} \\\\=\frac{20-9}{20\times 3}\\\\ =\frac{11}{60} \\= R.H.S$

∴ Left Hand Side = Right Hand Side

Hence,

$\{x=\frac{2}{3}, y=\frac{1}{5}\}$

The solution.

∴ For Equation ( 2 )

$L.H.S=\frac{2}{5}\times \frac{2}{3}+ \frac{1}{6}\times \frac{1}{5}\\\\\\=\frac{4}{15} -\frac{1}{30} \\\\=\frac{120+15}{15\times 30}\\\\= \frac{135}{450}\\ \\\\=\frac{3}{30}\\ \\= R.H.S$

∴ Left Hand Side = Right Hand Side

Hence ,

$\{x=\frac{2}{3}, y=\frac{1}{5}\}$

The solution.

For other Solutions we do not have Left Hand Side equal to Right Hand Side.

i.e Left Hand Side ≠ Right Hand Side

Hence Not a Solution.

5 0

2 years ago