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8 months ago

RT and UW are parallel lines

Mathematics

1 answer:

Veseljchak [2.6K]8 months ago

5 0

Answer: ∡RSQ and ∡TSQ

Supplementary angles are angles that add up to 180 degrees. We can see in the picture that both angles are located on the same line, and no other angles are involved, so they must equal 180.

We can also use the process of elimination:

∡RSQ and ∡UVS are congruent because they are consecutive angles.

∡RSQ and ∡WVX are also congruent because they are alternate exterior angles.
∡RSQ and ∡TSV are also congruent because they are vertical angles.

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Plz help I have to do a test tomorrow on this!

melomori [17]

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3 years ago

Alessandro wrote the quadratic equation –6 = x2 + 4x – 1 in standard form. What is the value of c in his new equation?

Black_prince [1.1K]

Answer:

Step-by-step explanation:

To write it in standard form, we set the equation equal to 0. To do this, we add 6 to each side:

-6+6 = x² + 4x - 1 + 6

0 = x² + 4x + 5

The related function is

y = x² + 4x + 5

The value of c in this function is 5.

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2 years ago

Two sides of an acute triangle meaure 5 inches and 8 inches. The length of the longest side is unknown. What is the greatest pos

gladu [14]

The greatest whole possible whole number length of the unknown side is 9 inches.

<h3>How to identify if a triangle is acute?</h3>

Let us have:

H = biggest side of the triangle

And let we get A and B as rest of the two sides.

Then we get:

$A^2 + B^2 < C^2$

then the triangle is acute

Two sides of an acute triangle measure as 5 inches and 8 inches

The length of the longest side is unknown.

We have to find the length of the unknown side

WE know that the longest side of any triangle is a hypotenuse

For an acute triangle we know:

$A^2 + B^2 < C^2$

Here in this sum,

a = 5 inches

b = 8 inches

c = ?

Substituting we get,

$A^2 + B^2 < C^2\\\\5^2 + 8^2 < C^2\\\\25 + 64= C^2$

c < 9

Hence, The greatest whole possible whole number length of the unknown side is 9 inches.

Learn more about angles;

brainly.com/question/14489478

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3 0

2 years ago

78 : 120 :: ? : 66 please give answer with explanation

yawa3891 [41]

Step-by-step explanation:

Method 1:

Given that:

78 : 120 :: ? : 66

Here,

Product of extremes = 78 and 66

Product of means = 120 and ?

so,

(78*66) = (120 * ?)

⇛5148 = 120 * ?

⇛5148 = 120?

⇛120? = 5148

Shift the number 120 from LHS to RHS, changing it's sign.

⇛? = 5148/120

Therefore, (?) = 42.9

Method 2:

78 : 120 :: ? : 66

Convert each ratio into fraction.

⇛78/120 = ?/66

On applying cross multiplication then

since, (a/b) = (c/d) ⇛cd = ad

Where, a = 78, b = 120, c = ? and d = 66

Now,

⇛(120)? = (78)66

⇛120? = 5148

⇛(?) = 5148/120

Therefore, (?) = 42.9

Answer: Hence the value of (?) for the given problem is 42.9.

Verification:

Check whether the value of (?) is true or false.

78 : 120 :: ? : 66

Substitute the value of (?).

⇛78:120 = 42.9:66

Product of extremes should be equal to product of means.

Product of extremes:- 78*66 = 5148

Product of means:- 120*42.9 = 5148

⇛5148 = 5148

LHS = RHS

Hence, verified.

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2 years ago

Which expressions are listed in the simplest form? Check all that supply

Nimfa-mama [501]

Add a picture please?

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2 years ago

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