Question

Please help with the following question:

Answer 1

Using it's concept, the probabilities are given as follows:

a) Type A die and orange: 1/10 = 0.1.

b) Blue: 23/30

c) Type B, if blue: 8/23.

What is a probability?

A probability is calculated as the number of desired outcomes in the experiment divided by the number of total outcomes in the experiment.

For item a, the probability that a type A dice is chosen is:

3/5.

As there are 5 dices, 3 of type A and 2 of type B.

The probability that a type A dice comes up orange is:

1/6.

As it has six faces, one of which is orange.

Then the probability of an orange type A dice being chosen is:

3/5 x 1/6 = 1/10 = 0.1.

For item b, the probability of blue is divided as follows:

• 5/6 of 3/5 -> type A.

• 4/6 of 2/5 -> type B.

Hence the probability of a blue dice is:

p = 5/6 x 3/5 + 4/6 x 2/5 = 23/30

For item c, we apply the conditional probability, hence the probability is given as follows:

p = (4/6 x 2/5)/(23/30) = (8/30)/(23/30) = 8/23.

Dividing the probabilities of type B and blue by the probability of blue.

More can be learned about probabilities at brainly.com/question/14398287

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