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Tasya [4]
11 months ago
11

Auto companies frequently test the safety of automobiles by putting themthrough crash tests to observe the integrity of the pass

enger compartment.If a 1000-kg car is sent toward a cement wall with a speed of 14 m/s and theimpact brings it to a stop in 8.00 x 10-2 s, with what average force is it,brought to rest?
Physics
1 answer:
e-lub [12.9K]11 months ago
4 0
Answer:

The average force that brings the car to rest is 175000N

Explanation:

The mass of the car, m = 1000 kg

Initial speed, u = 14 m/s

Final speed, v = 0 m/s (Since the car comes to a stop)

The time taken, t = 8 x 10^-2 s

The average force is calculated as:

\begin{gathered} F=\frac{m(u-v)}{t} \\ F=\frac{1000(14-0)}{8\times10^{-2}} \\ F=\frac{14000}{0.08} \\ F=175000N \end{gathered}

The average force that brings the car to rest is 175000N

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A perfectly flexible cable has length L, and initially it is at rest with a length Xo of it hanging over the table edge. Neglect
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6 0
3 years ago
g Initially, the motorcycle travels along a straight road with a speed of 35 m/s (this is almost 80 mph). The maximum decelerati
astraxan [27]

Given:

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Answer:

By substituting values in the equation, we get:

\rm \longrightarrow 0 = 35 + ( - 1.2)t \\  \\  \rm \longrightarrow  0 = 35 - 1.2t \\  \\  \rm  \longrightarrow 35 - 1.2t = 0 \\  \\  \rm  \longrightarrow 35- 35 - 1.2t = 0 - 35 \\  \\  \rm  \longrightarrow  - 1.2t =  - 35 \\  \\  \rm \longrightarrow  \dfrac{ - 1.2t}{ - 1.2}  =  \dfrac{ - 35}{ - 1.2}  \\  \\  \rm \longrightarrow  t = 29.167 \: s

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3 years ago
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Answer:

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