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emmainna [20.7K]
3 years ago
6

4. How much time does it take for a student running at a speed of 5 m/s to cover a distance of 2,000 m?

Physics
1 answer:
Monica [59]3 years ago
6 0

Answer:

6 Minutes 40 Seconds or 400 Seconds

Explanation:

Time to cover a distance of 5m = 1 Second

Time to cover a distance of 2000m = 2000÷5

= 400 Seconds

After converting 400 Seconds into minutes it will become 6 minutes 40 seconds.

Those who found this helpful please give me a Thanks to support me. So, I can explain other questions more clearly. If you don't want to mark me Brainliest don't mark. But, please give me a Thanks.

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blagie [28]

I to have no clue as well

4 0
3 years ago
1. A heat engine operates between two reservoirs at T2 = 600 K and T1 = 350 K. It takes in 1.00 x 103 J of energy from the highe
Alex73 [517]

Answer:

\Delta S_u=2.1429\ J.K^{-1}

W_c=416.67\ J

Explanation:

Given:

temperature of source reservoir, T_H=600\ K

temperature of sink reservoir, T_L=350\ K

energy absorbed from the source, Q_{in}=1000\ J

work done, W=250\ J

a.

<u>Now change in entropy of the surrounding:</u>

\Delta S_u=\frac{dQ_L}{T_L}

<em>Since heat engine is a device that absorbs heat from a high temperature reservoir and does some work giving out heat in the universe as the byproduct.</em>

\Delta S_u=\frac{Q_H-W}{T_L}

\Delta S_u=\frac{1000-250}{350}

\Delta S_u=2.1429\ J.K^{-1}

b.

<u>We know Carnot efficiency is given as:</u>

\eta_c=1-\frac{T_L}{T_H}

\eta_c=1-\frac{350}{600}

\eta_c=0.4167

<u>Now the Carnot work done:</u>

W_c=Q_H\times \eta_c

W_c=1000\times 0.4167

W_c=416.67\ J .......................(1)

c.

From eq. (1) we have the Carnot work, so the difference:

\Delta W=W_c-W

\Delta W=416.67-250

\Delta W=166.67\ J

Now, we find:

T_L.\Delta S_u=350\times 2.1429

5 0
3 years ago
Technician A says that the radiator should always be inspected for leaks and proper flow before installing a rebuilt engine. Tec
Slav-nsk [51]

Answer:

Both the technicians are right so option C is correct

Explanation:

Both the technicians are right so option C is correct

while installing a rebuilt engine, it is necessary to inspect the leaks and proper flow because if there is leak then cooling oil will flow out of the engine which results in engine heating. Secondly flow should be proper otherwise the oil will not reach to all parts and may cause heating of some parts of engine.

If the cooling fan is defective it won't be suck enough heat from engine and it will also cause heating.

8 0
3 years ago
Which is younger, the rock layers or the fault?
jeka94
<h2>FAULT</h2>

The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts. The fault labeled 'E' cuts through all three sedimentary rock layers (A, B, and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

6 0
3 years ago
Read 2 more answers
Pls help waves for physics
djverab [1.8K]

Answer:

b) 252 Hz or 260 Hz

c) 0.25 s

Explanation:

b) The frequency of the beats is 4 Hz, and one tuning fork has a frequency of 256 Hz.  Therefore, the second tuning fork is either 4 Hz lower or 4 Hz higher.

f = 252 Hz or 260 Hz

c) Period is the inverse of frequency.

T = 1/f

T = 1 / (4 Hz)

T = 0.25 s

8 0
3 years ago
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