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VashaNatasha [74]
3 years ago
8

What is the most common feature on the far side of the Moon?

Physics
2 answers:
Bond [772]3 years ago
6 0

Answer:

The far side of the moon is the hemisphere of the moon that always faces away from Earth. The far sides terrain is rugged with a multitude of impact craters and relativity few flat lunar Maria compared to the nera side. It is one of the largest craters in the solar system, the south pole- Aitken basin

Sati [7]3 years ago
3 0

The far side of the Moon is the hemisphere of the Moon that always faces away from Earth. The far side's terrain is rugged with a multitude of impact craters and relatively few flat lunar maria compared to the near side. It has one of the largest craters in the Solar System, the South Pole–Aitken basin.

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What is the difference between panda and rhino?​
olya-2409 [2.1K]

Answer:

Explanation:

The difference between panda and rhino are :

<u>panda</u>

1. The giant panda, also known as the panda bear, is a bear native to South Central China

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7 0
3 years ago
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How much work is done if you push a 200 N box across a floor with a force of 50 N for a distance of 20m
vovikov84 [41]
<h2>Answer: 1000 J</h2>

The Work W done by a Force F refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path.  

It should be noted that it is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter:  

1J=(1N)(1m)=Nm  

Now, when the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:  

W=(F)(d) (1)

When they are not parallel, both directions form an angle, let's call it \alpha. In that case the expression to calculate the Work is:  

W=Fdcos{\alpha} (2)

For example, in order to push the 200 N box across the floor, you have to apply a force along the distance d to overcome the resistance of the weight of the box (its 200 N).  

In this case both <u>(the force and the distance in the path) are parallel</u>, so the work W performed is the product of the force exerted to push the box F=50N by the distance traveled d. as shown in equation (1).

Hence:

W=(50N)(20m)  

W=1000Nm=1000J >>>>This is the work  

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enyata [817]

Answer:

I think it would be the 3rd or 4th one.

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