From reliable sources in the internet, the half-live of carbon-14 is given to be 5,730 years. In a span of 10,000 to 12,000 years, there are almost or little more than 2 half-lives. Thus, there should be
A(t) = A(0)(1/2)^t
where t is the number of half-lives, in this case 2. Thus, only about 1/4 of the original amount will be left.
Less gas will be collected because some of the gases will escape from the open cylinder valve.
Cylinders used to store carbon dioxide will have thicker walls than those of butane because of higher pressures.
<h3>What are compressed gases?</h3>
Compressed gases are gases which are compressed under high pressure in gas cylinders.
Cylinder valves are used to reduce the pressure of the compressed gases and in the process, some of the gas molecules escape.
Since the cylinder valve is open and the gas is collected at atmospheric pressure, less gas will be collected because some of the gases will escape.
Since, the carbon dioxide not liquefy under pressure compared to butane, the cylinders used to store carbon dioxide will have thicker walls than those of butane.
Learn more about compressed gases at: brainly.com/question/518065
Answer:
change in height is 1.664 mm
Explanation:
Given data
drops = 3.00 mm
diameter = 5.00 cm = 0.05 mm
decrease = 350 cm^3
temperature = 95°C to 44.0°C
to find out
the decrease in millimeters in level
solution
we will calculate here change in volume so we can find how much level is decrease
change in volume = β v change in temp ...............1
here change in volume = area× height
so = 
/4 × d² h
so we can say change in volume = /4 × d² × change in height .......2
so from equation 1 and 2 we calculate change in height
( β(w) -β(g) )× v× change in temp = /4 × d² × change in height
change in height = 4 × ( β(w) -β(g) ) v× change in temp / /4 × d²
put all value here
change in height = 4 × ( 210 - 27 )(350 ) 
× (95-44) / /4 × 0.05²
change in height is 1.664 mm
So if p=w/t
then 4400=(w)(200)
so you would multiply 4440•200 and get 880,000
Answer:
the eagle flew 1,025 km
Explanation:
since the eagle flew for 3 hours at 115 km/h it flew a total of 345 km during that time. During the 5 hours at 136 km/h the eagle flew a total of 680 km.
