Medicine to a patient. That should be calculated based on weight, strength/dosage and possibly other factors
Answer:
The electron cloud is mostly empty space
29.213 cm3
First, calculate the mass of the water used. You do this by subtracting the original mass of the flask from the combined mass of the water and flask, giving:60.735 g - 31.601 g = 29.134 g
So we now know we have 29.134 g of water. To calculate the volume of the flask, simply divide by the density of the water, giving:29.134 g / (0.9973 g/cm3) = 29.213 cm3
Answer: 12,600,000Cm
Explanation:
From the data's;
Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C
Distance = 7 micrometer, is equal to 0.0000070m
From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.
Then we have 1.8x10^¹² x 0.0000070= 12,600,000Cm
NB: The charges are identical.
Given from the problem :mass m = 413 kg;coefficient of friction u = 0.0163;acceleration due to gravity g = 9.8 m/s2;inclined angle @1 = 14.3;inclined angle @2 = 4.69;distance travelled d = 175 m;applied fore F = 410 N; the component of the force from the donkey in the direction of motion isF2 = F1
[email protected]= 397.2964498768165 N
Fy = N - mg
[email protected] = 0N = mg
[email protected] = 4037.964151113007 NFx = F2 - mg
[email protected] - f = mahere f = u N=65.8188156631420141
F2 - mg
[email protected] - f = maa = F2 - mg
[email protected] - f/ m=0.31923412183075155 m/s^2
work done by donkeyW = F2 d=69526.8787284428875 J
