Answer:
Acceleration of the meteorite, 
Explanation:
It is given that,
A Meteorite after striking struck a car, v = 0
Initial speed of the Meteorite, u = 130 m/s
Distance covered by Meteorite, s = 22 cm = 0.22 m
We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :
So, the deceleration of the Meteorite is 
. Hence, this is the required solution.
south = -(north)
Displacement = (4 km north) + (2 km south) + (5 km north) + (5 km south)
Displacement = (4 km north) - (2 km north) + (5 km north) - (5 km north)
Displacement = (4 - 2 + 5 - 5) km north
<u>Displacement = 2 km north </u>
Answer:
increased with the same rate as momentum
D is the answer
Velocity maybe negative or positive
while speed is always positive
For figure one the “+” are protons and the “-“ are electrons for the second one the middle is the nucleus and the other is the orbit
