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vekshin1
1 year ago
10

what process occurs in box a? what process occurs in box a? electron transport and oxidative phosphorylation oxidative phosphory

lation electron transport
Chemistry
1 answer:
miv72 [106K]1 year ago
8 0

oxidative phosphorylation occurs in a box ,Carbon dioxide and water are by-products of cellular respiration.

what is oxidative phosphorylation ?

  • During oxidative phosphorylation, electrons derived from NADH and FADH2 combine with O2, and the energy released from these oxidation/ reduction reactions is used to drive the synthesis of ATP from ADP.
  • Oxidative phosphorylation or electron transport-linked phosphorylation or terminal oxidation is the metabolic pathway in which cells use enzymes to oxidize nutrients, thereby releasing chemical energy in order to produce adenosine triphosphate. In eukaryotes, this takes place inside mitochondria
  • Oxidative Phosphorylation Steps
  1. Delivery of Electrons by NADH and FADH2. Reduced NADH and FADH2 transfer their electrons to molecules near the beginning of the transport chain. ...
  2. Electron Transport and Proton Pumping. ...
  3. Splitting of Oxygen to form Water. ...
  4. ATP Synthesis.
  • Oxidative phosphorylation provides most of the ATP that higher animals and plants use to support life and is responsible for setting and maintaining metabolic homeostasis.In the mitochondrion, what the proton gradient does is facilitate the production of ATP from ADP and Pi. This process is known as oxidative phosphorylation, because the phosphorylation of ADP to ATP is dependent on the oxidative reactions occurring in the mitochondria

to know more about oxidative phosphorylation follow

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Thus 0.06 moles of CH_4 will require=\frac{2}{1}\times 0.06=0.12moles  of O_2

Thus CH_4 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

As 1 moles of CH_4 give = 1 mole of CO_2

Thus 0.06 moles of CH_4 give =\frac{1}{1}\times 0.06=0.06moles  of CO_2

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