Answer:
28atm
Explanation:
Using Gay lussac's law equation as follows:
P1/T1 = P2/T2
Where;
P1 = initial pressure (atm)
T1 = initial temperature (K)
P2 = final pressure (atm)
T2 = final temperature (K)
Based on the information provided in this question;
P1 = 30.0 atm, T1 = 30.0°C, P2 = ?, T2 = 10.0°C
NOTE: Absolute temperature i.e. Kelvin is required for this law
T1 = 30°C + 273K = 303K
T2 = 10°C + 273K = 283K
Using P1/T1 = P2/T2
30/303 = P2/283
Cross multiply
P2 × 303 = 30 × 283
303P2 = 8490
P2 = 8490/303
P2 = 28.02
New pressure of the gas = 28atm
Answer:
It does not contain free mobile ions
Explanation:
Solid sodium chloride does not conduct electricity because it does not contain free mobile ions.
- Although sodium chloride is an ionic compound, in solid state, there is absence of free mobile ions.
- In aqueous solutions or in molten form, ionic compounds can conduct an electric current using free mobile ions as carriers.
- Therefore, they are electrolytes.
In solid state ions are arranged into crystal lattice and will not conduct a current of electricity.
Answer:
189 Joules
Explanation:
Applying,
Q = cm(t₂-t₁)............. equation 1
Where Q = Heat, c = specific heat capacity of water, m = mass of water, t₁ = Initial Temperature, t₂ = Final temperature.
From the question,
Given: m = 15 grams = 0.015 kg, t₁ = 21 °C, t₂ = 24 °C
Constant: c = 4200J/kg.°C
Substitute these values into equation 1
Q = 0.015×4200×(24-21)
Q = 0.015×4200×3
Q = 189 Joules
Answer is: the equilibrium concentrations fluorine anion are 0.004 M and lead cation are 0.002 M.<span>
Chemical reaction: PbF</span>₂(aq) → Pb²⁺(aq) + 2F⁻(aq).<span>
Ksp = 3,2·10</span>⁻⁸.
[Pb²⁺] = x.
[F⁻] = 2[Pb²⁺] = 2x<span>
Ksp = [Pb²</span>⁺] ·
[F⁻]².
Ksp = x · 4x².
3,2·10⁻⁸ = 4x³.
x = ∛3,2·10⁻⁸ ÷ 4.
x = [Pb²⁺] = 0,002M = 2·10⁻³ M.
[F⁻] = 2 · 0,002M = 0,004 M = 4·10⁻³ M.
