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2 years ago

A rigid cylinder with a movable piston contains a sample of helium gas. The temperature of the gas is held

Chemistry

2 answers:

Varvara68 [4.7K]2 years ago

8 0

Assuming ideal gas, we can label this system to follow the Boyle's Law. This Law can be applied to systems held at constant temperature. The formula used is: PV=k, where k is a constant. From the formula, P and V are inversely proprotional. So, if you graph P vs V, the graph would start from the top, then curves down towards the right.

S_A_V [24]2 years ago

6 0

The graph that shows the relationship between the volume and pressure of the gas is $\boxed{{\text{option (1)}}}$ . For the graph, refer to the attached image.

Further Explanation:

An ideal gas is a hypothetical gas that is composed of a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure. Helium is an example of an ideal gas.

Given information:

The temperature of the gas is kept constant.

To identify:

Graph of the relationship between pressure and volume of gas.

Boyle’s law:

It states that the volume of the gas is inversely proportional to its pressure if the temperature and the number of moles of gas remain constant. Higher the pressure of the gas, lower will be volume occupied by the gas and vice-versa. The mathematical form of Boyle’s law is,

$\boxed{{\text{P}} \propto \frac{1}{{\text{V}}}}$

Or,

${\text{PV}}={\text{k}}$

Here,

V is volume occupied by the gas.

P is the pressure of the gas.

k is a constant.

The graph between the pressure and volume of the helium gas is drawn in the attached image. So option (1) is the correct answer.

Learn more:

1. Which statement is true for Boyle’s law: brainly.com/question/1158880

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: Boyle’s law, P, V, k, pressure of gas, volume occupied by gas, constant, temperature, ideal gas.

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Calculate the mass defect for the formation of phosphorus-31. The mass of a phosphorus-31 nucleus is 30.973765 amu. The masses o

Nata [24]

Answer: The mass defect for the formation of phosphorus-31 is 0.27399

Explanation:

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

$\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M$

where,

$n_p$ = number of protons

$m_p$ = mass of one proton

$n_n$ = number of neutrons

$m_n$ = mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is $_{15}^{31}\textrm{P}$

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

$\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399$

Hence, the mass defect for the formation of phosphorus-31 is 0.27399

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2 years ago

Organelles_____are specialized structures that carry out particular jobs and functions?

sergejj [24]

Answer:

Cell or cellular

Explanation:

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3 years ago

Which symbol can be used to indicate the pressure at which a chemical reaction is carried out? 25 degrees Celsius over a right a

jolli1 [7]

Answer:

2 atm

Explanation:

Chemical reactions are carried out at a certain rate. Sometimes that rate is quite slow, so we want to speed things up, which is usually used by increasing temperature, increasing pressure or adding a catalyst (a substance that increases the rate without changing itself).

If this is the case, then, when writing a chemical equation, we state these special conditions over a right arrow.

Now let's look at the answers:

- 25°C is a value and unit of temperature

- ∆ is a symbol that denotes change

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- Pt is a chemical symbol for platinum, an element often used as a catalyst.

So, the correct answer is C) 2 atm

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3 years ago

Read 2 more answers

How many grams of Ar are there in 2.25 moles of Ar?

nydimaria [60]

Answer:

89.88 g

Explanation:

Atomic Mass of Ar: 39.948

Mass = moles * AM

Replacing moles = 2.25 and AM = 39.948 you get the mass of Ar:

Mass = 2.25 * 39.948

Mass = 89.88 g

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2 years ago

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DanielleElmas [232]

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3 years ago