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Katarina [22]
3 years ago
6

A rigid cylinder with a movable piston contains a sample of helium gas. The temperature of the gas is held

Chemistry
2 answers:
Varvara68 [4.7K]3 years ago
8 0
<span>Assuming ideal gas, we can label this system to follow the Boyle's Law. This Law can be applied to systems held at constant temperature. The formula used is: PV=k, where k is a constant. From the formula, P and V are inversely proprotional. So, if you graph P vs V, the graph would start from the top, then curves down towards the right. </span>
S_A_V [24]3 years ago
6 0

The graph that shows the relationship between the volume and pressure of the gas is \boxed{{\text{option (1)}}}. For the graph, refer to the attached image.

Further Explanation:

An ideal gas is a hypothetical gas that is composed of a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure. Helium is an example of an ideal gas.

Given information:

The temperature of the gas is kept constant.

To identify:

Graph of the relationship between pressure and volume of gas.

Boyle’s law:

It states that the volume of the gas is inversely proportional to its pressure if the temperature and the number of moles of gas remain constant. Higher the pressure of the gas, lower will be volume occupied by the gas and vice-versa. The mathematical form of Boyle’s law is,

\boxed{{\text{P}} \propto \frac{1}{{\text{V}}}}

Or,

{\text{PV}}={\text{k}}

Here,

V is volume occupied by the gas.

P is the pressure of the gas.

k is a constant.

The graph between the pressure and volume of the helium gas is drawn in the attached image. So option (1) is the correct answer.

Learn more:

1. Which statement is true for Boyle’s law: brainly.com/question/1158880

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Ideal gas equation

Keywords: Boyle’s law, P, V, k, pressure of gas, volume occupied by gas, constant, temperature, ideal gas.

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A sample 0. 100 moles of a gas is collected at at stp. What is the volume of the gas in liters?
andrew11 [14]

A sample 0. 100 moles of a gas is collected at at STP . 2.24 is the volume of the gas in liters.

The STP means standard temperature and pressure.

At STP,

Temperature = 0 °C =273 K

Pressure = 1 atm

We get value of volume by using ideal gas equation,

PV = nRT

  • P is the pressure of the gas = 1 atm
  • V is the volume occupied by the gas = ?
  • n is the number of the moles = 1 mole
  • T is the temperature of the gas = 273 K or  0 °C
  • R universal gas constant = 8.31 J/ mole × K

Calculation,

Since, one mole of a gas occupy 22.4 L volume at STP

So, for 0.1 mole volume occupy = 22.4L × 0.1 mole/1 mole =  2.24L

To learn more about volume at STP,

brainly.com/question/1542685

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1 year ago
Which bodies of water in the list are found to the west of the Philippines?​
bogdanovich [222]

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South China sea

Explanation:

To the west is the South China Sea, to the east the Philippine Sea and the Pacific Ocean, and to the south the Celebes Sea (or Sulawesi Sea).

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Determine the number of grams of carbon dioxide that can be formed from 0.500 grams of iron oxide and an excess of carbon.
Nimfa-mama [501]

Taking into account the reaction stoichiometry, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

2 Fe₂O₃ + 3 C → 4 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Fe₂O₃: 2 moles
  • C: 3 moles
  • Fe:4 moles
  • CO₂: 3 moles

The molar mass of the compounds is:

  • Fe₂O₃: 159.7 g/mole
  • C: 12 g/mole
  • Fe: 55.85 g/mole
  • CO₂: 44 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Fe₂O₃: 2 moles ×159.7 g/mole= 319.4 grams
  • C: 3 moles ×12 g/mole= 36 grams
  • Fe: 4 moles ×55.85 g/mole= 223.4 grams
  • CO₂: 3 moles ×44 g/mole= 132 grams

<h3>Mass of CO₂ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 319.4 grams of Fe₂O₃ form 132 grams of CO₂, 0.500 grams of Fe₂O₃ form how much mass of CO₂?

mass of CO_{2} =\frac{0.500 grams of Fe_{2}O_{3}x132 grams of CO_{2} }{319.4 grams of Fe_{2}O_{3}}

<u><em>mass of CO₂= 0.2066 grams</em></u>

Then, 0.2066 grams of CO₂ are formed from 0.500 grams of iron oxide and an excess of carbon.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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I’d guess 83? Braileist?
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