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1 year ago

Doughnuts are sold in bags and cartons.

Mathematics

1 answer:

VARVARA [1.3K]1 year ago

4 0

The formula for T in terms of B and C is T=4B+10C.

How are phrases converted into expressions and equations?

In order to give verbal explanations of mathematical operations:

Find any phrases or key words that denote an operation.

Add the individual processes together to create an expression or equation. Ensure that the sequence of events is maintained.

Let Doughnuts sold in bag be B

Let Doughnuts sold in cartons be C

As given in the question a bag can contain 4 Doughnuts

∴ it is 4B

as cartons can contain 10 Doughnuts

∴ it is 10C

As T is the total number of Doughnuts

∴ the formula is

T=4B+10C

To learn more about the phrases converted into expressions and equations from the given link

brainly.com/question/19718411

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How does the graph of g(x) = (x − 1)3 + 5 compare to the parent function f(x) = x3?

ser-zykov [4K]

Answer:

The original function was transformed by a a horizontal shift to the right in 1 unit, and also a vertical shift upwards of 5 units.

Step-by-step explanation:

Recall the four very important rules regarding translations (shifts) of the graph of functions:

1) In order to shift the graph of a function vertically c units upwards, we must transform f (x) by adding c to it.

2) In order to shift the graph of a function vertically c units downwards, we must transform f (x) by subtracting c from it.

3) In order to shift the graph of a function horizontally c units to the right, we must transform the variable x by subtracting c from x.

4) In order to shift the graph of a function horizontally c units to the left, we must transform the variable x by adding c to x.

We notice that in our case, The original function $f(x)=x^3$ has been transformed by "subtracting 1 unit from x", and by adding 5 units to the full function. Therefore we are in the presence of a horizontal shift to the right in 1 unit (as explained in rule 3), and also a vertical shift upwards of 5 units (as explained in rule 1).

5 0

3 years ago

Confused and need help

vodka [1.7K]

First, reflect the triangle across x

Then translate the triangle 1 unit to the right and 9 units down

8 0

3 years ago

A sandwich shop offers 4 different meats and 2 different cheeses. Suppose the sandwich shop offers 24 different meat-cheese sand

Sergio039 [100]

Answer:

Step-by-step explanation:

You would do this question like this.

4 meats * 2 cheeses * x breads = 24 different kinds of sandwiches.

8x = 24

8x/8 = 24/8

x = 3

There are 3 different kinds of breads.

4 0

3 years ago

What is it mean? a. 27.19 b. 27.29 c. 28.10 d. 28.11

Len [333]

Mean is average so you sum up all 4 numbers and divide by 4. Answer is 27.6725 or rounded 27.67

Have a nice day. Hope this helps.

3 0

2 years ago

The rates of on-time flights for commercial jets are continuously tracked by the U.S. Department of Transportation. Recently, So

tatyana61 [14]

Answer:

The probability that at least 13 flights arrive late is 2.5196 $\times 10^{-6}$ .

Step-by-step explanation:

We are given that Southwest Air had the best rate with 80 % of its flights arriving on time.

A test is conducted by randomly selecting 18 Southwest flights and observing whether they arrive on time.

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........$

where, n = number of trials (samples) taken = 18 Southwest flights

r = number of success = at least 13 flights arrive late

p = probability of success which in our question is probability that

flights arrive late, i.e. p = 1 - 0.80 = 20%

Let X = Number of flights that arrive late.

So, X ~ Binom(n = 18, p = 0.20)

Now, the probability that at least 13 flights arrive late is given by = P(X $\geq$ 13)

P(X $\geq$ 13) = P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18)

= $\binom{18}{13}\times 0.20^{13} \times (1-0.20)^{18-13}+ \binom{18}{14}\times 0.20^{14} \times (1-0.20)^{18-14}+ \binom{18}{15}\times 0.20^{15} \times (1-0.20)^{18-15}+ \binom{18}{16}\times 0.20^{16} \times (1-0.20)^{18-16}+ \binom{18}{17}\times 0.20^{17} \times (1-0.20)^{18-17}+ \binom{18}{18}\times 0.20^{18} \times (1-0.20)^{18-18}$

= $\binom{18}{13}\times 0.20^{13} \times 0.80^{5}+ \binom{18}{14}\times 0.20^{14} \times 0.80^{4}+ \binom{18}{15}\times 0.20^{15} \times 0.80^{3}+ \binom{18}{16}\times 0.20^{16} \times 0.80^{2}+ \binom{18}{17}\times 0.20^{17} \times 0.80^{1}+ \binom{18}{18}\times 0.20^{18} \times 0.80^{0}$

= 2.5196 $\times 10^{-6}$ .

7 0

3 years ago