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bija089 [108]
1 year ago
11

A piece of magnesium with a mass of 5.867 g was heated in a crucible which was open to the air. After the magnesium had combuste

d and allowed to cool down the product was found to have a mass of 8.956 g. Determine the empirical formula of the magnesium oxide formed.
Chemistry
1 answer:
morpeh [17]1 year ago
3 0

The empirical formula of the magnesium oxide formed is MgO

Here given data is piece of magnesium with a mass = 5.867 g  after the magnesium had combusted and allowed to cool down the product and mass = 8.956 g

The empirical formula is the simplest whole number ratio of atoms in a compound and the ratio of atoms is the same as the ratio of moles and when crucible react with magnesium and air means oxygen then magnesium reacts readily with oxygen in the air, to produce magnesium oxide then chemical reaction is written as follows:

2Mg + O₂ → 2MgO

and hence when it cool down automatically the mass of magnesium is more than 1st mass because in that oxygen of air are added and that's why MgO are made the empirical formula of the magnesium oxide formed is MgO

Know more about magnesium oxide formed.

brainly.com/question/28568488

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