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xxTIMURxx [149]
3 years ago
7

Malik had two tests on Wednesday. On the science test, each question was worth 4 points. On the math test, each question was wor

th 6 points. His score was -12 on each. On which test did he miss more item? Justify your answer.
Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0

Answer:

Science Test

Step-by-step explanation:

If he missed 12 points on each test (-12) he missed 2 questions on the math test and 4 questions on the sceince test.

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Helpppppppppppppppppppppppp
S_A_V [24]

Answer:

It is, D

Step-by-step explanation:

Your welcome for raising your test score

5 0
3 years ago
Read 2 more answers
Kenzie finds purple, blue, and silver space rocks while exploring, 2/3 of the rocks are purple and 3/4 of the remainder are blue
Nadya [2.5K]

Answer:

There were 36 space rocks in total.

Step-by-step explanation:

First, you need to find what fraction of the original rocks are silver.

If 2/3 are purple, then 1/3 of them are not.

If 3/4 of the remaining 1/3 are blue, then 3/4 x 1/3 = 3/12 rocks are blue.

2/3 of the rock are purple, 3/12 of them are blue, and the remaining is silver.

So, you need to do 2/3 - 3/12, then find common denominators so, 8/12 - 3/12 which = 1/12.

This means 1/12 of the rocks are silver. If there are silver rocks, you need to find a suitable equation that needs to be solved.

So:

1/12r = 3

r = 36 silver rocks

There were 36 space rocks in total.

hope this helps :)

3 0
3 years ago
Read 2 more answers
5.01 *10^-7-30*10^-9
777dan777 [17]

Answer:

\large\boxed{4.71\times10^{-7}}

Step-by-step explanation:

5.01\times10^{-7}-30\times10^{-9}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=5.01\times10^{-9+2}-30\times10^{-9}\\\\=5.01\times10^{-9}\cdot10^2-30\times10^{-9}\\\\=(5.01\cdot10^2)\times10^{-9}-30\times10^{-9}\\\\=(5.01\cdot100)\times10^{-9}-30\times10^{-9}\\\\=501\times10^{-9}-30\times10^{-9}\qquad\text{distribute}\\\\=(501-30)\times10^{-9}\\\\=471\times10^{-9}\\\\=4.71\cdot10^2\times10^{-9}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4.71\times10^{2+(-9)}\\\\=4.71\times10^{-7}

or

5.01\times10^{-7}-30\times10^{-9}\\\\=5.01\times10^{-7}-30\times10^{-7+(-2)}\\\\=5.01\times10^{-7}-30\times10^{-7}\cdot10^{-2}\\\\=5.01\times10^{-7}-(30\cdot10^{-2})\times10^{-7}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=5.01\times10^{-7}-\left(30\cdot\dfrac{1}{10^2}\right)\times10^{-7}\\\\=5.01\times10^{-7}-\left(30\cdot\dfrac{1}{100}\right)\times10^{-7}\\\\=5.01\times10^{-7}-(30\cdot0.01)\times10^{-7}\\\\=5.01\times10^{-7}-0.3\times10^{-7}\qquad\text{distribute}\\\\=(5.01-0.3)\times10^{-7}\\\\=4.71\times10^{-7}

4 0
3 years ago
Anika wants to determine the maximum number of tulip bulbs (t) she can purchase if each bulb costs $2.25. She will also need to
vovangra [49]

Answer:

The inequality to determine how many tulip bulbs Anika can purchase without spending more than $25.00 is:

2.25t+3.50t+15 \leq 25

Solving this;

=> 5.75t+15 \leq 25

=> 5.75t \leq 25-15

=> 5.75t \leq 10

=> t \leq 1.74

Rounding to 1.

No, Anika cannot spend the entire $25 if she buys the same number of bulbs and pots.

7 0
3 years ago
Read 2 more answers
Match the terms to their definition.
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3 years ago
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