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Sonja [21]
3 years ago
9

Whats the prime factorization for 59. Also whats the factorization for 61. Thank chu!

Mathematics
1 answer:
Ainat [17]3 years ago
8 0
1,59 and 1,61 are the prime factoratiozons for 59 and 61

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Simplify the expression given below: (18x^3-7)-(14x^3-36)
vovangra [49]

Answer:

2x6 + 4x5 + x4 + 11x3 + 2x2 + 4x + 4

Step-by-step explanation:

6 0
2 years ago
99,000 equals how much tens
In-s [12.5K]
9900  because you divide 99000 by 10
3 0
3 years ago
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Perfect Linear relationship between two or more independent variables is a violation of .... a. MLR.1 - Linearity in parameters
nexus9112 [7]

Answer:

b. MLR.3 - No perfect collinearity assumption

Step-by-step explanation:

There is an assumption that nothing in the error term should correlate with the explanatory variable (x) of interest and outcome variable of (y). It does not allow any linear relation between two or more variables. If there is a relation between the variable it the the violation of this assumption.  

4 0
3 years ago
50 POINTSS!!!!- The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement o
olga_2 [115]

Answer:

the first option

Step-by-step explanation:

solution:

distance: d=1/4 lc (because is a quarter of a circle)

length of the circumference: lc=2 pi r

pi: constant=3.14

radius of the circle: r=80 feet

replacing pi and r in the formula of lc:

lc=2 pi r

lc=2 (3.14) (80 feet)

lc=502.4 feet

replacing lc in the formula of d:

d=1/4 lc

d=1/4 (502.4 feet)

d=502.4/4 feet

d=125.6 feet

5 0
3 years ago
Read 2 more answers
In one town, the number of burglaries in a week has a poisson distribution with a mean of 1.9. find the probability that in a ra
tester [92]

Let X be the number of burglaries in a week. X follows Poisson distribution with mean of 1.9

We have to find the probability that in a randomly selected week the number of burglaries is at least three.

P(X ≥ 3 ) = P(X =3) + P(X=4) + P(X=5) + ........

= 1 - P(X < 3)

= 1 - [ P(X=2) + P(X=1) + P(X=0)]

The Poisson probability at X=k is given by

P(X=k) = \frac{e^{-mean} mean^{x}}{x!}

Using this formula probability of X=2,1,0 with mean = 1.9 is

P(X=2) = \frac{e^{-1.9} 1.9^{2}}{2!}

P(X=2) = \frac{0.1495 * 3.61}{2}

P(X=2) = 0.2698

P(X=1) = \frac{e^{-1.9} 1.9^{1}}{1!}

P(X=1) = \frac{0.1495 * 1.9}{1}

P(X=1) = 0.2841

P(X=0) = \frac{e^{-1.9} 1.9^{0}}{0!}

P(X=0) = \frac{0.1495 * 1}{1}

P(X=0) = 0.1495

The probability that at least three will become

P(X ≥ 3 ) = 1 - [ P(X=2) + P(X=1) + P(X=0)]

= 1 - [0.2698 + 0.2841 + 0.1495]

= 1 - 0.7034

P(X ≥ 3 ) = 0.2966

The probability that in a randomly selected week the number of burglaries is at least three is 0.2966

5 0
3 years ago
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