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Aliun [14]
3 years ago
12

Donna borrowed $10, 500 at a simple interest rate of 4% for 3 years to buy her new car. How much interest would Donna pay and ho

w much is the car altogether?
Mathematics
2 answers:
k0ka [10]3 years ago
7 0
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

Donna borrowed $10,500 at a simple interest rate of 4% for 3 years to buy her new car. How much interest would Donna pay and how much is the car altogether ?

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

\bullet Principal (P) = $10,500

\bullet Rate of interest (r) = 4%

\bullet Time (t) = 3 years

<h3>To Find:-</h3>

Interest of Donna and amount of car altogether.

<h2>Solution:-</h2>

We know,

{ \boxed{\rm \red {I \: = \frac{Prt}{100}}}}

\therefore I = \frac{10,500 \: × \: 4 \: × \: 3}{100}

I = \frac{126,000}{100}

I = $1260

Now,

Amount of the car = $ (10,500 + 1260)

= $ 11,760

<h3><u>$</u><u>1</u><u>2</u><u>6</u><u>0</u> interest would Donna pay and <u>$</u><u>1</u><u>1</u><u>,</u><u>7</u><u>6</u><u>0</u> is the car altogether. [Answer]</h3>
torisob [31]3 years ago
6 0

Step-by-step explanation:

We know that Interest = Principal×Rate×Time/100

So,

10,500×4×3/100

= 10,500×3/25 (by cancelling 100 by 4)

=31500/25

= 1260

Therefore,

$1260 Answer

hope it helps.....

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Answer

Find out the  which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

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