The value of f⁻¹(f(58)) is 58 and the value of the function f(f(5)) is 11
<h3>How to solve the function values?</h3>
As a general rule, we have:
f⁻¹(f(x)) = x
Substitute 58 for x
So, we have:
f⁻¹(f(58)) = 58
Hence, the value of f⁻¹(f(58)) is 58
Also, we have:
f(f(5))
From the table, we have:
f(5) = 9
So, we have:
f(f(5)) = f(9)
From the table, we have:
f(9) = 11
So, we have:
f(f(5)) = 11
Hence, the value of the function f(f(5)) is 11
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Answer:
3/14
Step-by-step explanation:
1st subtract the y's
the subtract the x's in the same order
-9 - 5 = -14
put the first result over the second
-3/-14 = 3/14
Answer: y2-y1/x2-x1=-1-3/3-3=-4/0=undefined.
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
1. Define word "zeros"
zeros = x-intercepts
2. Find x-intercepts
(-2, 0) and (-4, 0)
x-intercepts = -2, -4 or -4, -2