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miv72 [106K]
1 year ago
5

Find the coordinates of the vertices of the figure after the giver transformation: T<2,3>

Mathematics
1 answer:
Softa [21]1 year ago
8 0

Given:

Find-:

Coordinates after transformation

Explanation-:

I assume that is an x translation 2 to the right (positive horizontal ) and 3 up (positive vertical ) the vertices would be as follow

The vertices would be as:

H=\text{ }(1,-5)\rightarrow(3,-2)

The point L is:

L=(3,-1)\rightarrow(5,2)

The point N is:

N=(-1,-3)\rightarrow(1,0)

The point U is:

U=(1,2)\rightarrow(3,5)

So, the point all points is:

\begin{gathered} N^{\prime}=(1,0) \\  \\ U^{\prime}=(3,5) \\  \\ L^{\prime}=(5,2) \\  \\ H^{\prime}=(3,-2) \end{gathered}

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In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for
tatuchka [14]

Answer:

With a .95 probability, the margin of error is = 0.392

Step-by-step explanation:

Given -

In order to estimate the average time spent per student on the computer terminals at a local university, data were collected for a sample of 81 business students over a one-week period.

Sample size ( n ) =81

Standard deviation (\sigma ) = 1.8 hours

\alpha = 1 -.95 =.05

Z_{\frac{\alpha }{2}} = Z_{\frac{.05 }{2}} = 1.96           (Using Z table)

With a .95 probability, the margin of error is

Margin of error  =  Z_{\frac{\alpha }{2}}\frac{\sigma }{\sqrt{n}}

                          = Z_{\frac{.05 }{2}} \frac{1.8 }{\sqrt{81}}

                           = 1.96\times 0.2

Margin of error   = 0.392

   

8 0
3 years ago
Anthony travels from Newcastle to Manchester at an average speed of 65 miles per hour.
jasenka [17]

Answer:

See below

Step-by-step explanation:

Distance = rate * time

              = 65 m/hr * 2 1/4 hr = 146.25 miles

rate = distance / time

for Declan :   rate =  146.25 miles / (2 hrs + 35/60 min) = 56.61 mph

7 0
2 years ago
Jonathan and Byron both have comic book collection the number of books in the collection form a ratio 4:9 of Jonathan's to Byron
worty [1.4K]
Since the ratio is 4:9 your trying to find the sum. What I mean is that if it's 4 to 9, whats 20+9? =29. Do the same for 4. 20+4= 24. Now you find the difference in order to find how much does Byron have compared to Jonathan. So 29-24= 5
8 0
3 years ago
2 The points (-15, -3) and (-7, -1) both
hammer [34]

Answer:

The rate of change of f(x) with respect to x is 1/4

Step-by-step explanation:

What this question simply ask is to find the slope of the line that passes through the two points

to find this, we use the slope equation

we have this as;

m= (y2-y1)/(x2-x1)

(x1,y1) = ((-15,-3)

(x2,y2) = (-7,-1)

m = (-1 + 3)/(-7 + 15) = 2/8 = 1/4

3 0
3 years ago
#24, i am getting <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%26%5Cfrac%7B18%7D%7B7%7D%20
sveticcg [70]

It looks like you're talking about row-reducing an augmented matrix to solve the system of equations. Your answer is almost correct. The last row should read 0, 0, 1, 2/7.

The given system translates to

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 1 & -1 & 2 & 2 \\ 1 & 2 & -3 & 4 \end{array} \right]

Eliminate x from the last two rows by combining -2 (row 2) and row 1, and -2 (row 3) and row 1; that is,

(2x - 3y + z) - 2 (x - y + 2z) = 2 - 2 (2)

2x - 3y + z - 2x + 2y - 4z = 2 - 4

-y - 3z = -2

and

(2x - 3y + z) - 2 (x + 2y - 3z) = 2 - 2 (4)

2x - 3y + z - 2x - 4y + 6z = 2 - 8

-7y + 7z = -6

In augmented matrix form, this step yields

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & -7 & 7 & -6 \end{array} \right]

I'll omit these details in the remaining steps.

Eliminate y from the last row by combining -7 (row 2) and row 3 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 28 & 8 \end{array} \right]

Multiply the last row by 1/28 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Eliminate z from the second row by combining 3 (row 3) and row 2 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & 0 & -8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Multiply the second row by -1 :

\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Eliminate y and z from the first row by combining 3 (row 2), -1 (row 3), and row 1 :

\left[ \begin{array}{ccc|c} 2 & 0 & 0 & 36/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

Multiply the first row by 1/2 :

\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 18/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]

8 0
3 years ago
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