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2 years ago

Solve this question please

Mathematics

1 answer:

Iteru [2.4K]2 years ago

4 0

The value of y in y = 5x if the value of x doubles itself is y also doubles itself; option A

<h3>How to solve equation?</h3>

y = 5x

if x = 2

y = 5(2)

y = 10

if the value of x doubles, for instance, if x = 4

y = 5(4)

y = 20

y = 5/x

if x = 0.5

y = 5/0.5

y = 10

if the value of x triples, for instance, if x = 0.125

y = 5/x

= 5/0.125

y = 40

The value of y in y = 5/x if the value of x triples itself is y also triples itself; option B

Learn more about equation:

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3 years ago

Write a polynomial functionſ of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 1,3, and

otez555 [7]

Answer:

f(x) = $x^{4} - 8x^{3} + 24x^{2} - 32x + 15$

Step-by-step explanation:

First of all, if 2 - i is a zero, then so is 2 + i

All you need to do now is multiply (x - 1)(x - 3)(x - 2 + i)(x - 2 - i)

I will do part of that multiplication

(x - 2 + i)(x - 2 - i) = $x^{2}$ - 2x - xi - 2x + 4 + 2i + xi - 2i - $i^{2}$

= $x^{2}$ - 4x + 5

So, now (x - 1)(x - 3)( $x^{2}$ - 4x + 5) = $x^{4} - 8x^{3} + 24x^{2} - 32x + 15$

I will let you finish that multiplication. I did some and you can do some. OK?

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3 years ago

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Hope it helps! :)

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3 years ago

Read 2 more answers

Find the inverse of the function. f(x) = 6x3 - 8

Papessa [141]

$\bf f(x)=y=6x^3-8\qquad inverse\implies 
\begin{array}{lll}
x=&6y^3-8\\
&\uparrow\\
&\textit{switched variables} 
\end{array}
\\\\\\
x+8=6y^3\implies \cfrac{x+8}{6}=y^3\impliedby taking\ \sqrt[3]{\qquad }
\\\\\\
\sqrt[3]{\cfrac{x+8}{6}}=\sqrt[3]{y^3}\implies \sqrt[3]{\cfrac{x+8}{6}}=y\impliedby f^{-1}(x)$

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