Question

Which of the following can be used to calculate the volume of water inside the fish bowl?

Answer 1

The volume of a sphere can be calculated as

$V=\frac{4}{3}\pi r^3$

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

$V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3$

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

$r=\frac{AB}{2}=\frac{12}{2}=6$

Let's put it into our equation

$\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\ \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}$

The problem says to use

$\pi\approx\frac{22}{7}$

Then

$V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

$V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$