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VladimirAG [237]
3 years ago
14

Solve: sin^2 x + sin x cos x = 0

Mathematics
1 answer:
denis23 [38]3 years ago
3 0
Sin² x + sin x cos x = 0
sin x ( sin x + cos x ) = 0
sin x = 0 ;  x 1 = k π ;  k ∈ Z
sin x + cos x  = 0  / ²
sin² x + 2 sin x cos x + cos² x = 0
2 sin x cos x + 1  =0
sin ( 2 x ) = - 1
x = 3π / 2 + 2 kπ     / : 2
x 2 = 3π / 4 + kπ ;  k ∈ Z 


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For all values of x, f(x)=2x^2 and g(x)= x+1<br> Solve fg(x) = gf(x)
Andrej [43]

Answer:

-0.25

Step-by-step explanation:

→ Find fg(x)

2 ( x + 1 )² = 2x² + 4x + 2

→ Find gf(x)

2x² + 1

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4 0
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
ddd [48]

Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

y = -\frac{1}{2}\sqrt{x + 3}

Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

Multiply both sides by -2

-2 * x =-2 *  -\frac{1}{2}\sqrt{y + 3}

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y = 4x^2 - 3

The inverse has been solved. So, we need to replace y with f'(x)

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x \ge -3

Change inequality to \le

x \le -3

Hence, the inverse function is:

f'(x) = 4x^2 - 3 for x \le -3

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Step-by-step explanation:

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kobusy [5.1K]

Answer:

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Step-by-step explanation:

The expression shown evaluates as ...

  7 + 32(-5 +1)/2 = 7 +32(-4)/2 = 7 -128/2 = 7 -64 = -57

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If we assume your "32" is supposed to be 3², or 3^2, then the expression evaluates differently:

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Alex Ar [27]

Answer:

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Step-by-step explanation:

Subtract 2y from both sides, and now you have x=-2y-6.

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