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VladimirAG [237]
3 years ago
14

Solve: sin^2 x + sin x cos x = 0

Mathematics
1 answer:
denis23 [38]3 years ago
3 0
Sin² x + sin x cos x = 0
sin x ( sin x + cos x ) = 0
sin x = 0 ;  x 1 = k π ;  k ∈ Z
sin x + cos x  = 0  / ²
sin² x + 2 sin x cos x + cos² x = 0
2 sin x cos x + 1  =0
sin ( 2 x ) = - 1
x = 3π / 2 + 2 kπ     / : 2
x 2 = 3π / 4 + kπ ;  k ∈ Z 


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First, we are going to want to plug in the values we are given. In this case, we will end up with the equation:

6 = (4 - c) 2


From here, we can solve the equation to find c:

6 = 2(4 - c)

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We have found that c = 1.

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4 0
3 years ago
Read 2 more answers
Can someone please help me
Contact [7]

slope = (6 - 1)/(-2 - 1) = 5/-3 = -5/3

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Hope it helps

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The answer is:
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<span>Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is <span>−5</span></span><span>y=−5</span><span><span>(−5)</span>=8−<span>x
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Remove parentheses.<span>y=−5</span><span>−5=8−<span>x
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Solve for x in the second equation.<span>y=−5</span>
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The answer is <span>(13,−5<span>)            Please mark as Brainliest
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5 0
3 years ago
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