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GREYUIT [131]
3 years ago
6

Any large random sample from a group of people will be representative of the entire group.true false

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

true

Step-by-step explanation:

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A diagonal of a parellelogram measures 37 inches. The sides measure 35 inches and 1 foot. Is the parellelogram a rectangle? Expl
Monica [59]

Answer:

Yes, it is a rectangle

Step-by-step explanation:

12 ^2 +35^2 =37^2

3 0
4 years ago
Which statement correctly compares the function shown on this graph with the function y = -x+ 4?
s344n2d4d5 [400]

Answer:

I think the answer for this question is C

6 0
3 years ago
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Last year, Edward spent a total of $626.14 on his power bill. Rounding the total bill to the nearest tens place, approximate how
zlopas [31]

Answer:

He spent around  $ 52.17  in each month.

Step-by-step explanation:

Last year the power bill price = $ 626.14 ≈  $ 626

We know that in a year 12 months. so power bill of each month in last year is calculated as follows

Power \ bill \ of \ each \ month = \frac{Total \ bill \ of  \ the \ year}{12}

Power \ bill \ of \ each \ month = \frac{626}{12}

Power \ bill \ of \ each \ month =  $ 52.17

Therefore he spent around  $ 52.17  in each month.

7 0
4 years ago
Find the slope of the line y=5x+4
Tatiana [17]

Answer:

Slope = 5

Step-by-step explanation:

y = mx + b

m = slope

Slope = 5

6 0
3 years ago
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Which expression is a sum of cubes?
erik [133]

we know that

A polynomial in the form a^{3} +b^{3} is called a sum of cubes

so

Let's verify each case to determine the solution

<u>case A)</u> -64x^{6} y^{12} +125x^{16} y^{3}

we know that

-64=-4^{3}

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{16}=x^{15} *x=x*(x^{5})^{3} -------> is not a perfect cube

y^{3}= (y)^{3}

therefore

the case A) is not a sum of cubes

<u>case B)</u> -32x^{6} y^{12} +125x^{16} y^{3}

we know that

-32=-2^{5} -------> is not a perfect cube

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{16}=x^{15} *x=x*(x^{5})^{3} -------> is not a perfect cube

y^{3}= (y)^{3}

therefore

the case B) is not a sum of cubes

<u>case C)</u> 32x^{6} y^{12} +125x^{9} y^{3}

we know that

32=2^{5} -------> is not a perfect cube

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{9}=(x^{3})^{3}

y^{3}= (y)^{3}

therefore

the case C) is not a sum of cubes

<u>case A)</u> 64x^{6} y^{12} +125x^{9} y^{3}

we know that

64=4^{3}

x^{6}= (x^{2})^{3}

y^{12}= (y^{4})^{3}

125=5^{3}

x^{9}=(x^{3})^{3}

y^{3}= (y)^{3}

Substitute

4^{3}(x^{2})^{3}(y^{4})^{3} +5^{3}(x^{3})^{3}(y)^{3}

(4x^{2}y^{4})^{3} +(5x^{3}y)^{3}

therefore

<u>the answer is</u>

64x^{6} y^{12} +125x^{9} y^{3} is a sum of cubes

6 0
3 years ago
Read 2 more answers
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