Answers:
1/2a= 8
Multiply by 2/1 on both sides
1/2(2/1)a= 8(2/1)
Cross out 1/2 and 2/1 equals to a
a= 16
4n= 32
Divide by 4 for both sides
4n/4= 32/4
n= 8
3x= 36
Divide by 3 for both sides
3x/3= 36/3
x= 12
m/3= 2
Multiply by 3/1 for both sides
3/1*m/3= 2(3/1)
Cross out 3/1 and 3 becomes m
m= 6
x-8= 12
Move -8 to the other side. Sign changes from -8 to +8
x-8+8= 12+8
x= 20
48= 3k
Divide by 3 for both sides
48/3= 3k/3
k= 16
13/b= 0
Multiply by 1/13 for both sides.
13/b( 1/13)= 0(1/13)
b= 0
39= 13y
divide by 13 for both sides
39/13= 13y/13
y= 3
3.33 since we know 12 is for 40 we can set up an equation
Answer:
the area product is simply (3x+5).(x+7 which can multiply if desired to obtain highlight3x/2+ 26x + 35.
You can use Completion of the Square on the trinomial product to put this trinomial into standard form. You would want this form to be like (x-h)2 +k.
Answer:
47
Step-by-step explanation:
x is one of the three angles of a triangle. The other two are given as 95 and 38.
Together all three have to make 180 degrees.
x + 95 + 38 = 180
x + 133 = 180
x = 180 - 133
x = 47
Answer:
∠BIF = 126°
∠JBC = 63°
∠BJD = 117°
Step-by-step explanation:
adjacent angles in a rhombus add up to 180°
∠IBJ and ∠BIF are adjacent angles in a rhombus
thus,
∠IBJ + ∠BIF = 180°
54° + ∠BIF = 180
subtract 54 from both sides to isolate the variable
∠BIF = 126°
a line is 180°
thus, ∠IBA + ∠IBJ + ∠JBC = 180° as those three angles form a line
as the parallelograms are congruent, and we can visually notice that ∠IBA corresponds to angle ∠JBC, we can say that ∠IBA = ∠JBC
thus,
∠IBA + ∠IBJ + ∠JBC = 180°
54° + ∠JBC + ∠JBC = 180°
54° + 2∠JBC = 180
subtract 54 from both sides to isolate the variable and its coefficient
126° = 2∠JBC
divide 2 from both sides to isolate the variable
∠JBC = 63°
adjacent angles in a parallelogram add up to 180°
∠JBC and ∠BJD are adjacent angles in a parallelogram
∠JBC + ∠BJD = 180°
63° + ∠BJD = 180°
subtract 63 from both sides to isolate the variable
∠BJD = 117°
