Answer:
Part (A): The required equation will be: ![6d+20b=150](https://tex.z-dn.net/?f=6d%2B20b%3D150)
Part (B):The required equation will be: ![d=\frac{150-20b}{6}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B150-20b%7D%7B6%7D)
Part (C):The required equation will be: ![b=\frac{150-6d}{20}](https://tex.z-dn.net/?f=b%3D%5Cfrac%7B150-6d%7D%7B20%7D)
Step-by-step explanation:
Consider the provided information.
Let d represents number of packages of hot dogs and b represents the number of packages of hamburgers.
Part (a)
It is given that the cost of a package of hot dogs is $6 and cost of a package of hamburger is $20.
The required equation will be: ![6d+20b=150](https://tex.z-dn.net/?f=6d%2B20b%3D150)
Part (b) Solve the above equation for d.
Subtract 20b from both sides.
![6d=150-20b](https://tex.z-dn.net/?f=6d%3D150-20b)
Divide 6 from both sides.
![d=\frac{150-20b}{6}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B150-20b%7D%7B6%7D)
The required equation will be: ![d=\frac{150-20b}{6}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7B150-20b%7D%7B6%7D)
Part (c) Solve the equation for b.
Subtract 6d from both sides.
![20b=150-6d](https://tex.z-dn.net/?f=20b%3D150-6d)
Divide 20 from both sides, we get
![b=\frac{150-6d}{20}](https://tex.z-dn.net/?f=b%3D%5Cfrac%7B150-6d%7D%7B20%7D)
The required equation will be: ![b=\frac{150-6d}{20}](https://tex.z-dn.net/?f=b%3D%5Cfrac%7B150-6d%7D%7B20%7D)