Answer:
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The options for given question are as follow,
1) Methane molecules show hydrogen bonding.
<span>2) Ammonia molecules show hydrogen bonding. </span>
<span>3) Methane has stronger hydrogen bonding than ammonia. </span>
<span>4) Both the compounds do not show hydrogen bonding. </span>
<span>5) Both the compounds have strong hydrogen bonding.
</span>
Answer:
Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).
Explanation:
Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.
The Options are as follow,
<span>a.
it has 13 protons c. it has 13 neutrons </span>
<span>b.
it has 13 electrons d. it
has 7 neutrons</span>
Answer:
Option-d is the correct answer.
Explanation:
As we know that C-13 has a atomic mass of 13. Also, atomic mass is given as,
<span> Atomic Mass = # of Protons + # of Neutrons --- (1)</span>
Since;
Atomic Mass = 13
And,
# of protons = 6 (as number of protons = atomic number)
Putting values in equation 1,
13 = 6 - # of Neutrons
Solving for Number of Neutrons,
# of Neutrons = 13 - 6
# of Neutrons = 7
Answer:
ΔT = 20.06 °C
Explanation:
The equation used for this problem is as follow,
Q = m Cp ΔT ----- (1)
Where;
Q = Heat = 1.17 kJ = 1170 J
m = mass = 24.1 g
Cp = Specific Heat Capacity = 2.42 J.g⁻¹.°C⁻¹
ΔT = Change in Temperature = <u>??</u>
Solving eq. 1 for ΔT,
ΔT = Q / m Cp
Putting values,
ΔT = 1170 J / 24.1 g × 2.42 J.g⁻¹.°C⁻¹
ΔT = 20.06 °C
That would be the Ampere, named after a French scientist.
