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Natali [406]
2 years ago
6

does anyone know how to find the electron configuration of an element without using a periodic table?? group and period is alrea

dy given
Chemistry
2 answers:
snow_lady [41]2 years ago
8 0
For that you have to use the Aufbau principle

For example, writing the electronic configuration of Fe(28)

I recommend that you memorize the aufbau principle. Once you learn it, you don’t need anything else except the atomic number of the element to write it’s electronic configuration.
VARVARA [1.3K]2 years ago
5 0
Hi I’m sorryyyy I’m not sure
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For this assignment you will research a scientist that is from another continent. This scientist must have a different cultural
IceJOKER [234]

Albert Einstein's work focused on relativity theory and the as it could be applied to gravity, quantum mechanics and the theory of light.

<h3>Who is Albert Einstein?</h3>

The physicist Albert Einstein was born in Ulm Württemberg Germany in 1875. He migrated to the United States at the height of the Nazi regime in Germany where he became a professor of physics at Princeton University.

His work focused on the relativity theory and the as it could be applied to gravity, quantum mechanics and the theory of light. These ideas still remain fundamental in science today.

I became interested in the work of Albert Einstein because of the fact that is work is fundamental to the understanding of quantum mechanics and the idea of gravity. He laid the foundation upon which modern physics is built.

Learn more about Albert Einstein:brainly.com/question/2964376

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8 0
2 years ago
g A hydrogen atom initially in the n = 4 states emits a photon and makes a transition to the n = 2 level. What is the wavelength
Vinil7 [7]

<u>Answer:</u> The wavelength of the photon is 486.2 nm and it lies in the visible region

<u>Explanation:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant = 1.097\times 10^7m^{-1}

n_f = Higher energy level = 4

n_i = Lower energy level = 2

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{4^2} \right )\\\\\lambda =4.862\times 10^{-7}m

Converting this into nanometers, we use the conversion factor:

1m=10^9nm

So, 4.862\times 10^{-7}m\times (\frac{10^9nm}{1m})=486.2nm

As, the range of wavelength of visible light is 400 nm - 700 nm. So, the wavelength of the given photon lies in the visible region

Hence, the wavelength of the photon is 486.2 nm and it lies in the visible region

6 0
3 years ago
Molecular geometry of HCO2-
Anvisha [2.4K]

Answer:

Absolutely

Explanation:

6 0
3 years ago
Read 2 more answers
Which property of matter is conserved in chemical reactions and shown by balanced equations?
Julli [10]
It’s mass because the law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed.
4 0
3 years ago
Read 2 more answers
PLEASE HELP ME!<br> Determine the number of atoms in 4.27 g gold.
solmaris [256]

This can be done with some simple dimensional analysis. First you convert your gram of gold into moles of gold There are 196.97 grams of gold for every one mole of gold so you divide 4.27 by 196.67 to get 0.0217 moles of gold. You then multiply the moles of gold by Avogadro's number, 6.02 X 10^23. Avogadro's number indicates the number of atoms in one mole. Therefore, there are 1.307 X 10^22 atoms in 4.27 grams of gold.  

6 0
3 years ago
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