Water<span> can </span>dissolve salt<span> because the positive part of</span>water<span> molecules attracts the negative chloride ions and the negative part of </span>water<span> molecules attracts the positive sodium ions</span>
Use Ideal Gas equation since values are given in Pressure (P), Volume (V), Temperature (T).
P V = n R T ; n= PV / RT
You can't use 1 mole= 22.4 L equation. Temperature and pressure values are not standard. ( 1 atm, 0
To choose the value of R ( gas constant), check out the units of other values in the equation. They are in atm,liter, kelvin, and mole. So, its value is 0.082 L atm/ K mol.
P= 0.97 atm
V= 35.83 * 10 ⁻³ L (conversion from ml to, just multiplied by 10 ⁻³ )
R= 0.082 L atm/ K mol
T= (25.3 + 273) K ( recall Kelvin = Celcius + 273; K= °C + 273<span>)
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Substitute values into equation of n= PV / RT
n= (0.97 atm) (35.83 * 10 ⁻³ L) / (0.082 L atm/ K mol) (298.3 K)= 0.014 mole
The answer is 0.014 mole
Answer:
The presence of hydrogen bonding between molecules of a substance indicates that the molecules are polar. This means the molecules will be soluble in a polar solvent such as water. Some examples of polar molecules which can hydrogen bond are ammonia ( NH3 ) and methanol ( CH3OH ).
I think the answer should be C
There’s two type of black out “like passing out “ or when it dark
Answer:
1) 1/√K
2) 1/K
3) √K
Explanation:
As general rules of operation of equilibrium constants:
For the reaction:
A + B ⇄ C + D; Equilibrium constant = K
C + D ⇄ A + B; K' = 1/K
2A + 2B ⇄ 2C + 2D; K'' = K²
Thus, as equilibrium constant of:
2CO2 + 4H2O ⇄ 2CH3OH + 3O2
Is K:
1) CH3OH + 3/2 O2 ⇄ CO2 + 2H2O
K' = 1 / K^(1/2) = 1/√K
2) 2CH3OH + 3O2 ⇄ 2CO2 + 4H2O
K' = 1/K
3) CO2 + 2H2O ⇄ CH3OH + 3/2 O2
K' = K^(1/2) = √K
