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3 years ago

7

What is the name of tetranitrogen dichloride?

1 answer:

DanielleElmas [232]3 years ago

3 0

Not sure good luck on finding someone too help you

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The molarity of a sodium hydroxide (NaOH) solution is 0.2 M. The molar mass of NaOH is 40 g/mol. If the solution contains 20 g o

mote1985 [20]

Answer:

$\large \boxed{\text{2.5 L}}$

Explanation:

1. Calculate the moles of NaOH.

$\text{Moles} = \text{20 g} \times \dfrac{\text{1 mol}}{\text{40 g}} = \text{0.50 mol}$

2. Calculate the volume of NaOH

$\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is $\large \boxed{\textbf{2.5 L}}$}$

7 0

3 years ago

Read 2 more answers

How many kJ of heat are released by the reaction of 25.0 g of Na2O2(s) in the following reaction? (M = 78.0 g/mol for Na2O2)

solong [7]

-20.16 KJ of heat are released by the reaction of 25.0 g of Na2O2.

Explanation:

Given:

mass of Na2O2 = 25 grams

atomic mass of Na2O2 = 78 gram/mole

number of mole = $\frac{mass}{atomic mass of 1 mole}$

= $\frac{25}{78}$

=0. 32 moles

The balanced equation for the reaction:

2 Na2O2(s) + 2 H2O(l) → 4 NaOH(aq) + O2(g) ∆Hο = −126 kJ

It can be seen that 126 KJ of energy is released when 2 moles of Na2O2 undergoes reaction.

similarly 0.3 moles of Na2O2 on reaction would give:

$\frac{126}{2}$ = $\frac{x}{0.32}$

x = $\frac{126 x 0.32}{2}$

= -20.16 KJ

Thus, - 20.16 KJ of energy will be released.

6 0

3 years ago

A balloon of helium gas in Alabama has a volume of 22.4 L at 26°C and a 1.03 ATM how big with a balloon get if is transported to

Dimas [21]

Answer:

The final volume of the balloon is = 28.11 L

Explanation:

Initial pressure $P_{1}$ = 1.03 atm = 104.325 K pa

Initial temperature $T_{1}$ = 26 °c = 299 K

Initial volume $V_{1}$ = 22.4 L

Final temperature $T_{2}$ = 22 °c = 295 K

Final pressure $P_{2}$ = 0.81 atm = 82 K pa

We know that

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

Put all the values in above formula we get

$\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}$

$V_{2}$ = 28.11 L

This is the final volume of the balloon.

8 0

2 years ago

According to newtons third law forces always occur in equal but____ pairs?

arsen [322]

'Every action has an equal but opposite reaction' They are equal, but opposite.

8 0

2 years ago

Fill in the gaps. Will give BRAINLIEST and 5 starss!!!

Stells [14]

First gap is BY USING MAGNETS
2nd is ELECTROLYSIS
3rd is EVAPORATION

7 0

2 years ago