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3 years ago

I don't understand how to evaluate 2.28 please help me anyone?

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

5 0

Well, since the first 2.28 is in between the two lines you must find is absolute value.
Absolute value is how many places a number is away from 0.

So the absolute value of 2.28 is 2.28, its just its own number.

If you were working with negative numbers though, for example -7, the absolute value would be 7 because it is 7 spaces away from 0.

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2 years ago

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4 years ago

Read 2 more answers

How much cardboard is needed to make the tissue box above? Square inches 8 3 3

Katen [24]

The amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

<h3>What is the surface area of cuboid?</h3>

Let the three dimensions(height, length, width) be x, y,z units respectively.

The surface area of the cuboid is given by

$S = 2(a\times b + b\times c + c\times a)$

For this case, tissue box is almost cuboid shaped.

Also, its dimensions are given being 8 inches, 3 inches and 3 inches.

Suppose we measure the amount of cardboard needed in terms of area, then, the amount of cardboard needed to make that box(without any whole, full cuboid) is equal to the area of its surface(either outer or inner if we assume 0 inches thickness of cardboard),

Thus, we get:

Amount of cardboard needed = surface area of cuboid box with dimensions 8 by 3 by 3 (in inches)

= $2(8 \times 3 + 3 \times 3 + 3 \times 8) = 114 \: \rm in^2$

Thus, the amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

Learn more about surface area of cuboid here:

brainly.com/question/13522634

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3 years ago

The width of a rectangle measures (5v-10w)centimeters, and its length measures (2v+3w)centimeters. Which expression represents t

kiruha [24]

Answer:the perimeter of the rectangle =A) (−14w+14v) centimeters

Step-by-step explanation:

Step 1

The perimeter of a Rectangle is given as 2 (l+ w)

If Length = 2v+3w centimeters.

and width =5v-10wcentimeters

Then Perimeter =2 (2v+3w + 5v-10w)

Perimeter=2(7v -7w)

Perimeter= 14v - 14w or can be written as -14w +14v

8 0

3 years ago