Question

Travels 11,000 feet along a dark desert highway if the car averages 84 mph find the amount of time to cover this distance

Answer 1

The time taken by traveler to cover the distance is,

$t=\frac{d}{v}$

Substitute the known values,

$\begin{gathered} t=\frac{(11000\text{ ft)}}{(84\text{ mph)(}\frac{1.46667\text{ ft/s}}{1\text{ mph}})_{}} \\ \approx89.3\text{ s} \end{gathered}$

Therefore, the time taken by traveler to cover the distance is 89.3 s.