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3 years ago

15

Car A of mass 1200kg traveling at 10m/s , collided in too the back of the car B, which is stationary. Following the collision,.

The two cars stick together and travel at 6m/s. What is the mass of a car B?

2 answers:

Nina [5.8K]3 years ago

4 0

Answer:

Car B has a mass of 800 kg.

General Formulas and Concepts:

<u>Momentum</u>

Law of Conservation of Momentum: $\displaystyle m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_{f}$

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] m₁ = 1200 kg

[Given] v₁i = 10 m/s

[Solve] m₂

[Given] v₂i = 0 m/s

[Given] vf = 6 m/s

<u>Step 2: Solve for m₂</u>

Substitute in variables [Law of Conservation of Momentum]: (1200 kg)(10 m/s) + m₂(0 m/s) = (1200 kg + m₂)(6 m/s)
Multiply: 12000 kg · m/s = (1200 kg + m₂)(6 m/s)
Isolate m₂ term: 2000 kg = 1200 kg + m₂
Isolate m₂: 800 kg = m₂

rewona [7]3 years ago

3 0

Answer:

Explanation:

Caraofmass1200kg

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You are listening to the radio when one of your favorite songs comes on, so you turn up the volume. If you managed to increase t

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To solve this problem we need to apply the corresponding sound intensity measured from the logarithmic scale. Since in the range of intensities that the human ear can detect without pain there are large differences in the number of figures used on a linear scale, it is usual to use a logarithmic scale. The unit most used in the logarithmic scale is the decibel yes described as

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3 years ago

A container in the shape of a cube 10.0 cm on each edge contains air (with equivalent molar mass 28.9 g/mol) at atmospheric pres

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Answer:

a) m = 1.174 grams

b) F_g = 0.01151 N

c) F_c = 1013 N

Explanation:

Given:

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- Pressure of air P = 101.3 KPa

- Temperature of air T = 300 K

- Universal Gas constant R = 8.314 J/kgK

Find:

(a) the mass of the gas

(b) the gravitational force exerted on it

(c) the force it exerts on each face of the cube

(d) Why does such a small sample exert such a great force? (6%)

Solution:

- Compute the volume of the cube:

V = L^3 = 0.1^3 = 0.001 m^3

- Use Ideal gas law equation and compute number of moles of air n:

P*V = n*R*T

n = P*V / R*T

n = 101.3*10^3 * 0.001 / 8.314*300

n = 0.04061 moles

- Compute the mass of the gas:

m = n*M

m = 0.04061*28.9

m = 1.174 grams

- The gravitational force exerted on the mass of gas is due to its weight:

F_g = m*g

F_g = 1.174*9.81*10^-3

F_g = 0.01151 N

- The force exerted on each face of cube is due its surface area:

F_c = P*A

F_c = (101.3*10^3)*(0.1)^2

F_c = 1013 N

- The molecules of a gas have high kinetic energy; hence, high momentum. When they collide with the walls they transfer momentum per unit time as force. Higher the velocity of the particles higher the momentum higher the force exerted.

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3 years ago

A parallel-plate capacitor has square plates that are 8.00cm on each side and 4.20mm apart. The space between the plates is comp

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Answer:

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Explanation:

Given that

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d= 4.2 mm

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