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Setler79 [48]
2 years ago
13

What is fundamental questioning came nowcfy_tuhq_wjt​

Physics
1 answer:
Nadya [2.5K]2 years ago
8 0

Answer:

juz taking points nvm no sry for u cos u too wasted point

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A force vector points due east and has a magnitude of 150 newtons. A second force is added to . The resultant of the two vectors
balandron [24]

Answer:

a. 240 N due east

b. 540 N due west

Explanation:

Let east be the reference direction

(a) if the resultant force has a magnitude of 390 N and points east, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of

390 - 150 = 240 N

(b) if the resultant force has a magnitude of 390 N and points west, it would be -390N is eastern reference, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of

-390 - 150 = -540 N

This force would point west

6 0
2 years ago
Please answer! thank you!
lesantik [10]

Answer:

Maybe A.... I'm not sure

Explanation:

8 0
2 years ago
Read 2 more answers
A rocket car on a horizontal rail has an initial mass of 2500 kg and an additional fuel mass of 1000 kg. At time t0 the rocket m
slamgirl [31]

Answer: Acceleration of the car at time = 10 sec is 108 m/s^{2} and velocity of the car at time t = 10 sec is 918.34 m/s.

Explanation:

The expression used will be as follows.

M\frac{dv}{dt} = u\frac{dM}{dt}

\int_{t_{o}}^{t_{f}} \frac{dv}{dt} dt = u\int_{t_{o}}^{t_{f}} \frac{1}{M} \frac{dM}{dt} dt

       = u\int_{M_{o}}^{M_{f}} \frac{dM}{M}

v_{f} - v_{o} = u ln \frac{M_{f}}{M_{o}}

v_{o} = 0

As, v_{f} = u ln (\frac{M_{f}}{M_{o}})

u = -2900 m/s

M_{f} = M_{o} - m \times t_{f}

           = 2500 kg + 1000 kg - 95 kg \times t_{f}s

           = (3500 - 95t_{f})s

v_{f} = -2900 ln(\frac{3500 - 95 t_{f}}{3500}) m/s

Also, we know that

     a = \frac{dv_{f}}{dt_{f}} = \frac{u}{M} \frac{dM}{dt}

        = \frac{u}{3500 - 95 t} \times (-95) m/s^{2}

        = \frac{95 \times 2900}{3500 - 95t} m/s^{2}

At t = 10 sec,

v_{f} = 918.34 m/s

and,   a = 108 m/s^{2}

3 0
2 years ago
A 524-Hz longitudinal wave in air has a speed of 345 m/s. (a) What is the wavelength? (b) How much time is required for the phas
zhuklara [117]

Answer: a) 152 cm

b) 0.725 ms

c) 10°

Explanation:

Given

Frequency of the wave, f = 524 Hz

Speed of the wave, v = 345 m/s

Wavelength of the wave, λ = ?

The relation for wavelength is given by

λ = f/v, on substituting

λ = 524 / 345

λ = 1.52 m or 152 cm

T = 1/v

T = 0.0029 s

T = 2.9 ms.

Note that the phase change is 90°, thus the time required to change the phase by 90° is

t = 2.9 * (90 / 360)

t = 2.9 * 0.25

t = 0.725 ms

The phase difference at a particular instance 4.4 cm apart is

= (4.4 / 152) * 360

= 0.02895 * 360

= 10.422°

a) 152 cm

b) 0.725 ms

c) 10°

5 0
3 years ago
If energy cannot go away, why don’t things move forever?)
HACTEHA [7]

Answer:

because energy is used to keep the things in place

5 0
2 years ago
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