The surface area of a cube is:
S = 6l², making l the subject:
l = √(S/6)
While the volume is:
V = l³
If we substitute l to get:
V = (√(S/6))³
√(S/6) = ³√V
S/6 = (³√V)²
S = 6(³√V)² ⇒ 6V^(2/3)
Answer:
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Explanation:
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Position displacement velocity acceleration are vectors and the rest are scalars
Answer:
0.6983 m/s
Explanation:
k = spring constant of the spring = 0.4 N/m
L₀ = Initial length = 11 cm = 0.11 m
L = Final length = 27 cm = 0.27 m
x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m
m = mass of the mass attached = 0.021 kg
v = speed of the mass
Using conservation of energy
Kinetic energy of mass = Spring potential energy
(0.5) m v² = (0.5) k x²
m v² = k x²
(0.021) v² = (0.4) (0.16)²
v = 0.6983 m/s
