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3241004551 [841]
4 years ago
13

Least Common Multiple for 6 and 10.

Mathematics
2 answers:
Alik [6]4 years ago
5 0
Oh the LCM is 30. I know this because 6 times 5 is 30 and 10 times three is 30
IrinaVladis [17]4 years ago
4 0
The least common multiple of any two numbers is the first number they both have in common.
A multiple of any number means the number is self-adding, or creating multiples.

With this information, lets get ready to solve.

We'll do the first 5 of each number.

6 = 6, 12, 18, 24, 30.

10 = 10, 20, 30, 40, 50.

They both have 30 in common first, so 30 is the least common multiple.

I hope this helps!
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7(w+2)=-6(2w-1)+3w<br>solve for w.​
Goshia [24]

9514 1404 393

Answer:

  w = -1/2

Step-by-step explanation:

Eliminate parentheses, collect terms:

  7w +14 = -12w +6 +3w . . . eliminate parentheses

  7w +14 = -9w +6 . . . . . . . . collect terms

  16w +14 = 6 . . . . . . . . . . . . add 9w

  16w = -8 . . . . . . . . . . . . . . . subtract 14

  w = -1/2 . . . . . . . divide by 16, reduce the fraction

__

<em>Check</em>

  7(-1/2 +2) = -6(2(-1/2) -1) +3(-1/2)

  7(3/2) = -6(-2) -3/2

  21/2 = 12 -3/2 . . . . . true, answer checks OK

8 0
3 years ago
A different building has office space for rent that doesn't not require a one time fee, but you must pay rent of $1000 per month
Pavel [41]

Answer: First building at 17.5 months

Step-by-step explanation:

Months you can stay in the first building.

One time fee of $1,000 reduces the amount you have to;

= 15,000 - 1,000

= $14,000

Rent is $800. Months you can stay;

= 14,000/800

= 17.5 months

Months you can stay in second building;

Rent is $1,000 and no one time fee;

= 15,000/1,000

= 15 months

<em>You can stay longer in the first building for 17.5 months. </em>

3 0
3 years ago
Which two tables represent the same function?
Natalka [10]
Can you make it more clear to read
4 0
4 years ago
Need help saying Korean ​
Talja [164]

Answer: koh-rien

Step-by-step explanation:

6 0
3 years ago
Hey, Its the same person. This is Algebra 2. Please Help!
suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

     = \frac{(x + 4)(2x-3)}{x+4} ← cancel (x + 4) on numerator/ denominator

     = 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

There is a zero at ( \frac{3}{2}, 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( \frac{3}{2}, 0 )

7 0
3 years ago
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