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3241004551 [841]
3 years ago
13

Least Common Multiple for 6 and 10.

Mathematics
2 answers:
Alik [6]3 years ago
5 0
Oh the LCM is 30. I know this because 6 times 5 is 30 and 10 times three is 30
IrinaVladis [17]3 years ago
4 0
The least common multiple of any two numbers is the first number they both have in common.
A multiple of any number means the number is self-adding, or creating multiples.

With this information, lets get ready to solve.

We'll do the first 5 of each number.

6 = 6, 12, 18, 24, 30.

10 = 10, 20, 30, 40, 50.

They both have 30 in common first, so 30 is the least common multiple.

I hope this helps!
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How many 1/3 are in 7/3?
lisabon 2012 [21]

Answer:

7

Step-by-step explanation:

6 0
3 years ago
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A factory robot recently examined some bulbs, of which 2 were flawed and 36 were not. Considering this data, how many flawed bul
Vladimir [108]

Answer: 1 bulb

Step-by-step explanation:

Using the proportion of flawed bulbs in the first scenario, you can get the number of flawed bulbs in the other bath.

First scenario total bulbs = 2 + 36 = 38

Proportion of flawed bulbs = 2/38 = 1/19

In a batch of 19, the flawed bulbs are;

= 1/19 * 19

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3 0
2 years ago
Hurry Quick, help me do this problem. I don't understand how to do this so please help! (Problem in photo)
matrenka [14]

Answer:

1) The system of equations is 5x+4y=75 and x+y=18

2) The first number is 3 and the second number is 15

Step-by-step explanation:

1) Let be "x" the first number and "y" the second number.

Remember that:

a- The word "times" indicates multiplication.

b- A sum is the result of an addition.

c- "Is" indicates this sign:  =

Then, the sum of 5 times "x" and 4 times "y" is 75, can written as:

5x+4y=75

And "The sum of the two numbers is 18" can written as:

x+y=18

Therefore, the System of equations is:

\left \{ {{5x+4y=75} \atop {x+y=18}} \right.

2) You can use the Elimination Method to solve it:

- Multiply the second equation by -5, add the equations and then solve for "y":

\left \{ {{5x+4y=75} \atop {-5x-5y=-90}} \right.\\......................\\-y=-15\\\\y=15

- Substitute the value of "y" into any original equation and solve for "x":

x+15=18\\\\x=18-15\\\\x=3

7 0
3 years ago
Abigail made a quilt that has the area of 4,800 sq. inches. The length of the quilt is 1 1/3 times the width of the quilt. What
Aliun [14]
For this case we model the problem as a rectangle.
 The area of the rectangle is given by:
 A = (w) * (l)
 Where,
 w: width
 l: long
 Substituting values we have:
 4800 = (w) * ((1 1/3) * w)
 We rewrite:
 w ^ 2 = 4800 / (1 1/3)
 w ^ 2 = 3600
 w = root (3600)
 w = 60 in
 The long will be then:
 l = (1 1/3) * w
 l = (1 1/3) * (60)
 l = 80 in
 Answer:
 
the dimensions of the quilt are:
 
w = 60 in
 l = 80 in
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3 years ago
Giving 40 points who help me
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Answer:

D is the answer. There are 5 boxes, that each has 3 filled in.

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