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3 years ago

Least Common Multiple for 6 and 10.

Mathematics

2 answers:

Alik [6]3 years ago

5 0

Oh the LCM is 30. I know this because 6 times 5 is 30 and 10 times three is 30

IrinaVladis [17]3 years ago

4 0

The least common multiple of any two numbers is the first number they both have in common.
A multiple of any number means the number is self-adding, or creating multiples.

With this information, lets get ready to solve.

We'll do the first 5 of each number.

6 = 6, 12, 18, 24, 30.

10 = 10, 20, 30, 40, 50.

They both have 30 in common first, so 30 is the least common multiple.

I hope this helps!

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Rich is driving from Philadelphia to Pittsburgh at 70 mph and Michelle is driving from Pittsburgh to Philadelphia at 65 mph. If

nignag [31]

The answer is C. 2 hours and 15 minutes. Please refer to the attached document to see the image for better understanding of solution.

Philadelphia = Point A
Pittsburgh = Point B
X = distance traveled by Michelle
(305-X) = distance traveled by Rich

The general formula used is:

$distance = velocity(time)$
$s = v(t)$

Assigning values gives 2 equations:

For Michelle: $X = 65(t)$
For Rich: $(305-X) = 70(t)$

Substituting both equations gives:

X = 146.852 miles
t = 2.26 hours or approximately 2 hours and 15 minutes

Download docx

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Answer:

21 1/2 yd

Step-by-step explanation:

43/4 + 43/4 = 21 1/2 yd

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3 years ago

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Need help with number 11 ASAP!!!!

Korolek [52]

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Dual-energy X-ray absorptiometry (DXA) is a technique for measuring bone health. One of the most common measures is total body b

kramer

Answer:

(a)

$\bar x = 0.0075$

$s = 0.0049$

(b)

B. The sample is too small to make judgments about skewness or symmetry.

Step-by-step explanation:

Given:

$n = 8$

$\begin{array}{ccccccccc}{} & {S} & {u} & {b} &{j} & {e} & {c} & {t} & {s} &{Operator} & {1} & {2} & {3} & {4} & {5} & {6} & {7} & {8} & {1} & 1.326 & 1.337 & 1.079 & 1.229 & 0.936 & 1.009 & 1.179 & 1.289 & 2 & 1.323 & 1.322 & 1.073 & 1.233 & 0.934 & 1.019 & 1.184 & 1.304 \ \end{array}$

Solving (a):

First, calculate the difference between the recorded TBBMC for both operators:

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.

The mean is then calculated as:

$\bar x = \frac{\sum x}{n}$

$\bar x = \frac{0.003 + 0.015 + 0.006 + 0.004 + 0.002 + 0.010 + 0.005 + 0.015}{8}$

$\bar x = \frac{0.06}{8}$

$\bar x = 0.0075$

Next, calculate the standard deviation (s).

This is calculated using:

$s = \sqrt{\frac{\sum (x - \bar x)^2}{n}}$

So, we have

$s = \sqrt\frac{(0.003 - 0.0075)^2 + (0.015 - 0.0075)^2+ (0.006- 0.0075)^2+ ....... + (0.005- 0.0075)^2+ (0.015- 0.0075)^2 }{8}$ $s = \sqrt\frac{0.00019}{8}$

$s = \sqrt{0.00002375$

$s = 0.0049$

Solving (b):

Of the given options (A - E), option B is correct because the sample is actually too small

6 0

3 years ago