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Nat2105 [25]
3 years ago
10

Suppose there is a 1.1 drop in temperature for every thousand feet that an airplane climbs into the sky. If the temperature on t

he ground is ​60.5, what will be the temperature when the plane reaches an altitude of ​11,000?
Mathematics
1 answer:
Alex73 [517]3 years ago
7 0

Answer:

<h2>48.4° C</h2>

Step-by-step explanation:

Step one:

We are told that there is 1.1° drop in temperature for each 1000 ft climb.

since the given altitude is 11,000ft,

hence there =(11000/1000)*1.1

= 11*1.1

=12.1°C drops in temperature.

Therefore, given that the temperature on the ground is 60.5° C

The temperature above is 60.5-12.1=48.4° C

<u>The plane reaches an altitude of ​11,000 is 48.4° C</u>

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Step-by-step explanation:

Since Tony the Tiger makes $25 an hour, in 2 hours, he would make $50. Both of them, when divided, equal 25, the constant of proportionality.

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Explain the level of uncertainties involve in concept of probability. The next generation of miniaturized wireless capsules with
RUDIKE [14]

Answer:

a) the probability that Both motors will operate satisfactorily in the capsule 0.6222

b) the probability that One motor will operate satisfactorily and the other will not is 0.3556

Step-by-step explanation:

Given that;

total number of motors N = 10

number of motors will not operate satisfactory m = 2

number of motors randomly selected n = 2

let X be number of motors will that will not operate successfully

here, X≅Hyper geometric (x; N,n,m)

The probability mass function of x is;

P (X = x)=  { m }   {N - m }

                  {x }    {n - x}

        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

                     { N }

                     { n  }

a)

the probability that both motors will operate satisfactorily in the capsule i.e no motor will not operate satisfactory

so

P(X= 0)  = { 2 }    { 10 - 2 }

                 {0 }    { 2 - 0}

        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

                     { 10 }

                     { 2  }

so

P (X = 0)  = { 2 }   { 8}

              {  0 }   { 2  }

        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

                     { 10 }

                     { 2  }

p(P= 0)=1×28 / 45 = 28/45 = 0.6222

Therefore the probability that Both motors will operate satisfactorily in the capsule 0.6222

b)

the probability that one motor will operate satisfactorily and the other will not.

P(X=1)  = { 2 }   { 10 - 2 }

              {  1 }    { 2 - 1  }

        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

                     { 10 }

                     { 2  }

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              {  1 }   { 1  }

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                     { 10 }

                     { 2  }

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