A possible scale for the drawing can be
1 inches : 3 feet.
2 inches : 6 feet
or 3 inches to 9 feet
or 0.5 inches to 1.5 feet.
Hope this helps :)
<h3>
Answer: 41</h3>
Work Shown:
f(x) = 6x^2 - 13
f(x) = 6(x)^2 - 13
f(-3) = 6(-3)^2 - 13 ... replace every x with -3; use PEMDAS to simplify
f(-3) = 6(9) - 13
f(-3) = 54 - 13
f(-3) = 41
The diameter of the new rubber ball, to the nearest foot, must be D = 4.0 ft (in the case of the maximum cost).
<h3>
How to find the diameter of the ball?</h3>
Remember that for a sphere of diameter D, the surface area is:
A = 4*pi*(D/2)^2
In this case, the cost is $0.02 per square foot, and the company wants to expend (at maximum) $1 per ball, so first we need to solve:
$0.02*A = $1
A = $1/$0.02 = 50
So the surface of the ball must be 50 square feet.
Then we solve:
50ft^2 = 4*3.14*(D/2)^2
D = 2*√(50 ft^2/(4*3.14)) = 4.0 ft
If you want to learn more about spheres, you can read:
brainly.com/question/10171109
Use pythagorean theory
a^2 + b^2 = c^2
5^2 + 12^2 = 169
square root of 169 is 13
the missing side length is 13 in
Answer:
678899
Step-by-step explanation:
