Answer:
the actual pressure is 31.09
Complete question:
What is the actual pressure when Ali's gauge shows 33.58
Step-by-step explanation:
Given,
Ali's tyre presser gauge show a reading 8% higher than the actual pressure.
Ali's gauge shows 33.58.
Let the actual pressure be x.
According to problem,
{ [If 8% increasing of a no ⇒ The number becomes = 
of the number}
x= 
x=31.09
Therefore, the actual pressure is 31.09
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Let's assume you have supplement angle
Now when you talk about multiplication you can simply say...
And that will give you the answer.
