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Serhud [2]
3 years ago
12

Identify the system of equations that is satisfied by the given ordered pair.

Mathematics
1 answer:
iris [78.8K]3 years ago
8 0
Cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
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50, 40<br> What’s the GCF of these numbers
dexar [7]

Answer:

10

Step-by-step explanation:

40=2 x 2 x 2 x 5

50=2 x 5 x 5

therefore, GFC = 2x5

GFC= 10

3 0
3 years ago
Read 2 more answers
Choose the equation below that represents the line passing through the point (1, -4) with a slope of 1/2
tatiyna

For this case we have that by definition, the line equation of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the statement we have:

m = \frac {1} {2}

Thus, the equation is of the form:

y = \frac {1} {2} x + b

We substitute the given point and find "b":

-4 = \frac {1} {2} (1) + b\\-4 = \frac {1} {2} + b\\-4- \frac {1} {2} = b\\b = - \frac {9} {2}

Finally, the equation is of the form:

y = \frac {1} {2} x- \frac {9} {2}

Answer:

y = \frac {1} {2} x- \frac {9} {2}

6 0
3 years ago
What is the median of the data set: {24, 31, 12, 38, 12, 15}A)12B)19.5C)24D)23.5
QveST [7]

Answer: B: 19.5

Step-by-step explanation:

This data set is an even data set meaning that you're going to have to add and divide, so you put your data set in ascending order (highest # to lowest #) so 12,12,15,24,31,38 its an even data set so you're going to put them in groups (remember your finding the median, the middle numbers) so you have 12,12 (one group) and 31,38 (another group) (basically make it even!!) so now you're left with the middle numbers, you have to add them and then divide them by 2 so (15+24) ÷2 and you get your answer !!

6 0
2 years ago
The indefinite integral can be found in more than one way. First use the substitution method to find the indefinite integral. Th
Fantom [35]

Answer:

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C

Step-by-step explanation:

To find:

∫6x^5(x^6-2)\,dx

Solution:

Method of substitution:

Let x^6-2=t

Differentiate both sides with respect to t

6x^5\,dx=dt

[use (x^n)'=nx^{n-1}]

So,

∫6x^5(x^6-2)\,dx = ∫ t\,dt = \frac{t^2}{2}+C_1 where C_1 is a variable.

(Use ∫t^n\,dt=\frac{t^{n+1} }{n+1} )

Put t=x^6-2

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1

Use (a-b)^2=a^2+b^2-2ab

So,

∫6x^5(x^6-2)\,dx = \frac{1}{2}(x^6-2)^2+C_1=\frac{1}{2}(x^{12}+4-4x^6)+C_1=\frac{x^{12} }{2}-2x^6+2+C_1=\frac{x^{12} }{2}-2x^6+C

where C=2+C_1

Without using substitution:

∫6x^5(x^6-2)\,dx = ∫6x^{11}-12x^5\,dx = \frac{6x^{12} }{12}-\frac{12x^6}{6}+C=\frac{x^{12} }{2}-2x^6+C

So, same answer is obtained in both the cases.

7 0
2 years ago
Classify the polynomial by its degree and the number of terms. 8x²- 3y + 7
katen-ka-za [31]

Answer:

2nd degree

Step-by-step explanation:

8 0
3 years ago
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