1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sveta [45]
3 years ago
7

Three electromagnetic waves arrive at a point from the same direction. They are polarized parallel to an x axis, and their elect

ric fields at the point are E1 = A sin(ωt) for wave 1, E2 = B sin(ωt + φ2) for wave 2, and E3 = C sin(ωt + φ3) for wave 3. Here t is time. The constants are A = 3.0 µV/m, B = 4.0 µV/m, C = 5.0 µV/m, ω = 7.0 × 106 rad/s, φ2 = π/4, and φ3 = π/2. What is the amplitude (in µV/m) of the electric field that results from the interference of the three waves?
Physics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

E₁ = 9.759{\mu\frac{V}{m}}sin(7.0 × 10⁶ t)

Explanation:

Given:

E₁ = 3sin(7.0 × 10⁶ t)

E₂ = 4sin(7.0 × 10⁶ t + 45°)

E₃ = 5sin(7.0 × 10⁶ t + 90°)

Now,

the net vertical component of Electric field E is

E_v= 3sin(0°) + 4sin(0° + 45°) + 5sin(0° + 90°)

or

E_v = 7.828 {\mu\frac{V}{m}}

Now,

the net horizontal component of Electric field E is

E_h = 3cos(0°) + 4cos(0° + 45°) + 5cos(0° + 90°)

or

E_h = 5.828 {\mu\frac{V}{m}}

Therefore, the resultant Electric field is

E_{R} =\sqrt{E_v^2+E_h^2}

or

E_{R} =\sqrt{7.828^2+5.828^2}

or

E_{R} =9.759\ {\mu\frac{V}{m}}

Now, the phase angle is given as:

\phi=\tan^{-1}\frac{0}{9.759} =

hence,

E₁ = 9.759{\mu\frac{V}{m}}sin(7.0 × 10⁶ t)

You might be interested in
Calculate the molarity of a 10. 0% cacl₂ solution. The density of the solution is 1. 0835 g/cm³.
brilliants [131]

The molarity of 10% CaCl2 is 0.9%

concentration of the given salt CaCl₂ = 10%

Density of a solution = 1.0835 g/cm³

Volume = m / d

= 100 / 1.0835

= 92.29 litres

Density = mass / volume

1.0835 × 92.29 = mass

mass = 99.99 gram

Thus the molarity can be calculated by = moles of solute / volume of solution multiplied by 100

= 0.9008/ 92.29 X 100 %

= 0.009 X 100 %

= 0.9 %

The molarity of 10% CaCl2 is 0.9%

To know more about density and molarity you may visit the link which is mentioned below:

brainly.com/question/10710093

#SPJ4

5 0
1 year ago
A 1350 kg uniform boom is supported by a cable. The length of the boom is l. The cable is connected 1/4 the
olchik [2.2K]

Answer:

Tension= 21,900N

Components of Normal force

Fnx= 17900N

Fny= 22700N

FN= 28900N

Explanation:

Tension in the cable is calculated by:

Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium

FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)

Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)

Ftorque= 2/3FBcostheta+ 4/3FWcostheta

Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°

Ftorque= 21900N

b) components of Normal force

Efx=FNx-FTcos(90-theta)=0 static equilibrium

Fnx=21900cos(90-55)=17900N

Fy=FNy+ FTsin(90-theta)-FB-FW=0

FNy= -FTsin(90-55)+FB+FW

FNy= -21900sin(35)+(1350+2250)×9.81=22700N

The Normal force

FN=sqrt(17900^2+22700^2)

FN= 28.900N

4 0
3 years ago
A 20 cm-radius ball is uniformly charged to 71 nC.
artcher [175]

Answer:

Part a)

\rho = 2.12\mu C/m^3

Part b)

q_1 = 1.11 nC

q_2 = 8.88 nC

q_3 = 71 nC

Part c)

E_1 = 3996 N/C

E_2 = 7992 N/C

E_3 = 15975 N/C

Explanation:

Part a)

As we know that charge density is the ratio of total charge and total volume

So here the volume of the charge ball is given as

V = \frac{4}{3}\pi R^3

V = \frac{4}{3}\pi(0.20)^3

V = 0.0335 m^3

now the charge density of the ball is given as

\rho = \frac{71 nC}{0.0335} = 2.12\mu C/m^3

Part b)

Now the charge enclosed by the surface is given as

q = \rho V

at radius of 5 cm

q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.05)^3

q = 1.11 nC

at radius of 10 cm

q = (2.12 \mu C/m^3)(\frac{4}{3}\pi(0.10)^3

q = 8.88 nC

at radius of 20 cm

q = 71 nC

Part c)

As we know that electric field is given as

E = \frac{kq}{r^2}

so we have electric field at r = 5 cm

E_1 = \frac{(9\times 10^9)(1.11 nC)}{0.05^2}

E_1 = 3996 N/C

electric field at r = 10 cm

E_2 = \frac{(9\times 10^9)(8.88 nC)}{0.10^2}

E_2 = 7992 N/C

electric field at r = 20 cm

E_3 = \frac{(9\times 10^9)(71 nC)}{0.20^2}

E_3 = 15975 N/C

3 0
3 years ago
Learning Goal:
enot [183]

Answer:

A. U_0 = \dfrac{\epsilon_0 A V^2}{2d}

B. U_1 = \dfrac{\epsilon_0 A V^2}{6d}

C. U_2 = \dfrac{K\epsilon_0 A V^2}{2d}

Explanation:

The capacitance of a capacitor is its ability to store charges. For parallel-plate capacitors, this ability depends the material between the plates, the common plate area and the plate separation. The relationship is

C=\dfrac{\epsilon A}{d}

C is the capacitance, A is the common plate area, d is the plate separation and \epsilon is the permittivity of the material between the plates.

For air or free space, \epsilon is \epsilon_0 called the permittivity of free space. In general, \epsilon=\epsilon_r \epsilon_0 where \epsilon_r is the relative permittivity or dielectric constant of the material between the plates. It is a factor that determines the strength of the material compared to air. In fact, for air or vacuum, \epsilon_r=1.

The energy stored in a capacitor is the average of the product of its charge and voltage.

U = \dfrac{QV}{2}

Its charge, Q, is related to its capacitance by Q=CV (this is the electrical definition of capacitance, a ratio of the charge to its voltage; the previous formula is the geometric definition). Substituting this in the formula for U,

U = \dfrac{CV^2}{2}

A. Substituting for C in U,

U_0 = \dfrac{\epsilon_0 A V^2}{2d}

B. When the distance is 3d,

U_1 = \dfrac{\epsilon_0 A V^2}{2\times3d}

U_1 = \dfrac{\epsilon_0 A V^2}{6d}

C. When the distance is restored but with a dielectric material of dielectric constant, K, inserted, we have

U_2 = \dfrac{K\epsilon_0 A V^2}{2d}

6 0
3 years ago
What are the factors of works?
olga2289 [7]

Answer:

Explanation:

The seven factors are work load, family life, transportation, compensation policy and benefits, colleagues and supervisor, working environment and working condition and career growth.

4 0
3 years ago
Other questions:
  • Calculate the velocity of the object in the graph during the following time interval 0-6 seconds. Also, during which time interv
    14·1 answer
  • Can anyone tell me the ans of this question also please
    13·2 answers
  • You are asked to determine the density of a liquid. What lab equipment is most helpful to find density of the liquid?
    11·2 answers
  • How does the tilt of Earth's axis affect how the sun's rays strike Earth?
    11·1 answer
  • What is the anion of the ionic compound NaC2H3O2<br><br> thank you!
    5·1 answer
  • Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.
    9·1 answer
  • What is the purpose of the traveling gnome experiment? (Search up traveling gnome experiment)
    10·1 answer
  • Solve for x and y algebraically:<br>x + y = 8 and 3x + 2y = 21​
    7·2 answers
  • A group of students left school at 8:00 am on a field trip to a science museum 90 miles away. Which best describes the average s
    13·1 answer
  • What is the potential difference across lamp 1
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!