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3 years ago

The relationship between frequency, wavelength, and speed holds for light waves because

2 answers:

7 0

B. all forms of electromagnetic radiation travel at a single speed in a vacuum, which is the speed of light (c).

Therefore wavelength and frequency are inversely proportional to each other, with their product equaling the speed of light (c).

λν=c where λ is the wavelength, ν is the frequency and c is the speed of light

defon3 years ago

5 0

Answer:

Explanation:

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A charge feels a 7.89 x 10-7 N force when it moves 2090 m/s at a 29.4° angle to a 4.23 x 10-3 T magnetic field. What is the amou

tamaranim1 [39]

We have that the amount of the charge q is

$q=1.8*10^{-7}$

From the Question we are told that

Force $F=7.89 x*10^{-7}$

Velocity $V=2090m/s$

Angle $\theta=29.4$

Magnetic field $B=4.23 * 10^{-3} T$

Generally, the equation for Force F is mathematically given by

$F=qVBsin\theta\\\\q=\frac{F}{VBsin\theta}$

$q=\frac{7.89 x*10^{-7}}{4.23 * 10^{-3} T*sin29.4*2090m/s}$

$q=1.8*10^{-7}$

In conclusion

The amount of the charge q is

$q=1.8*10^{-7}$

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3 years ago

Read 2 more answers

How to understand Planck law?

AVprozaik [17]

Do you have a book about it? or if you have a dictionary?

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3 years ago

The use of a laser beam to seal leaky blood vessels and to prevent the growth of new ones in diabetic retinopathy is called lase

emmainna [20.7K]

The answer is photocoagulation.

The use of a laser beam to seal leaky blood vessels and to prevent the growth of new ones in diabetic retinopathy is called laser photocoagulation.

What is photocoagulation?

A minimally invasive method used to treat numerous retinal illnesses is photocoagulation of the retina, also known as retinal laser photocoagulation. The retina may expand due to aberrant leaky blood vessels developing across it in a number of disorders. Laser photocoagulation uses thermal energy above 65 °C to burn the retinal tissue by creating thermal burns. This can prevent the retina from being damaged by the bleeding blood vessels. In addition to causing fibrosis, laser photocoagulation can also seal retinal tears. Laser photocoagulation is typically unable to recover already lost vision in cases of retinal disease, but it can slow the progression of the condition, lower the chance of further vision loss, and preserve residual vision. The likelihood of problems following the operation is quite minimal.

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1 year ago

Read 2 more answers

2. A pair of narrow, parallel slits sep by 0.25 mm is illuminated by 546 nm green light. The interference pattern is observed on

Agata [3.3K]

Answer:

for the first interference m = 1 y = 2,839 10-3 m

for the second interference m = 2 y = 5,678 10-3 m

Explanation:

The double slit interference phenomenon, for constructive interference is described by the expression

d sin θ = m λ

where d is the separation between the slits, λ the wavelength and m an integer that corresponds to the interference we see.

In these experiments in general the observation screen is L >> d, let's use trigonometry to find the angles

tan θ = y / L

with the angle it is small,

tan θ = sin θ / cos θ = sin θ

we substitute

sin θ = y / L

d y / L = m λ

the distance between the central maximum and an interference line is

y = m λ L / d

let's reduce the magnitudes to the SI system

λ = 546 nm = 546 10⁻⁹ m

d = 0.25 mm = 0.25 10⁻³ m

let's substitute the values

y = m 546 10⁻⁹ 1.3 / 0.25 10⁻³

y = m 2,839 10⁻³

the explicit value for a line depends on the value of the integer m, for example

for the first interference m = 1

the distance from the central maximum to the first line is y = 2,839 10-3 m

for the second interference m = 2

the distance from the central maximum to the second line is y = 5,678 10-3 m

3 0

3 years ago

A student is doing a lab experiment in which she uses diffraction to measure the width of a shaft of her hair. She shines a 530

professor190 [17]

Answer:

.09 mm

Explanation:

In case of diffraction by single slit with width a the width of central maxima is given below

width = 2 λD/a

where λ is wavelength of light , D is distance of screen , a is width o slit

substituting the given values

14 x 10⁻³ = $\frac{2\times530\times10^{-9}\times1.2}{a}$

a = .09 mm

b) If a is greater , width of central maxima will be less wide.

7 0

3 years ago