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lawyer [7]
2 years ago
11

A state park charges $5 per car plus $1 per person as an admission fee. The total charged for a car with x people is f(x) = x +

5. How will the graph of this function change if the per car charge is changed to $8 per car?
Mathematics
1 answer:
Studentka2010 [4]2 years ago
7 0

Answer:

Given: f(x) = x + 5

If this function changes  to $8 per car then

The function: f(x) = x + 8

The concept of equation of straight line:  y= mx + b

where b represents the y-intercept

In the equation above, the y-intercept changed from 5 to 8.

The graph will shift 3 units up

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kolezko [41]

Answer:

48 cupcakes were put on the plates.

Step-by-step explanation: 6 x 8 = 48

I hoped this answer helped you solve your problem!

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8 0
3 years ago
Jaun has 105 feet of rope he needs to cut into sections 7/8 feet long . how many sections can be cut
AVprozaik [17]

The answer is 120 sections.

Here's an explanation:

The rope is 105 feet long, and each section needs to be 7/8 feet. So to find the number of sections, you need to divide 105 by 7/8. 105 divided by 7/8 gives you the quotient 120. So there are 120 sections.

5 0
3 years ago
Select all that apply.
Kryger [21]

Answer:

Your answer would be

1 \times 3 = 3

And

3 \times 5 = 15

Step-by-step explanation:

Hope this helps. If I am wrong, REPORT ME PLEASE.

6 0
2 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
Plsss help me I don’t understand!!
inna [77]

Answer:

11

Step-by-step explanation:

in the "score" section all you do is add all them up. And because there is a negative for ALL the numbers, all you do is add a negative after you add all the SCORES

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3 years ago
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