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defon
3 years ago
11

What fraction is 1 degree?

Mathematics
1 answer:
allsm [11]3 years ago
7 0
1/360
Hope this helps please mark this as brainliest answer
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The volume of a rectangular box is 330 cubic inches. The length on one side of the top is 11 inches, and the height of the box i
Fiesta28 [93]

Answer: 110 square inches.

Step-by-step explanation:

The volume of a rectangular box would be:

V=length*width*height

In this case, we know the volume, the length and the height, and we don't know the width, so we're going to isolate it:

width=\frac{V}{length*height}

Substituting the data:

width=\frac{330}{11*3} =10in

This width is also the width of the top of the box, so the area of the top would be:

A=length*width\\A=11*10\\A=110in^{2}

5 0
3 years ago
What is the measure of each angle in the circle?<br><br> 30°<br> 90°<br> 72°<br> 60°
klio [65]

Answer:

72°

Step-by-step explanation:

The circle is divided into 5 parts.

A circle measures 360°.

360/5 = 72°

hope this helps!! p.s. i really need brainliest :)

6 0
2 years ago
Read 2 more answers
Match the reasons with the statements in the proof.
natta225 [31]
<span>1. m∠6=m∠8, b||c
Given

2. m∠7=m∠8
</span><span>If lines ||, corresponding angles =.
</span><span>
3. m∠6=m∠7
</span>Substitution 
<span>
4. a||b </span>
If alternate interior angles equal, then lines ||. 
6 0
3 years ago
Read 2 more answers
Can someone help me please!!
hodyreva [135]

Answer:

  1. idk

Step-by-step explanation:

i just need points :/ v

8 0
3 years ago
Practice Skills_ Simplifying Inequality1. 3( 1/2 - y) = 3/5 + 15y. What isthe solution to the given inequality?
Angelina_Jolie [31]

3( 1/2 - y) = 3/5 + 15y

Applying distributive property:

3*1/2 - 3y = 3/5 + 15y

3/2 - 3y = 3/5 + 15y

3/5 is adding on the right, then it will subtract on the left

3y is adding on the left, then it will subtract on the right

3/2 - 3/5 = 15y + 3y

15/10 - 6/10 = 18y

9/10 = 18y

18 is multiplying on the right, then it will divide on the left

9/10*1/18 = y

1/10*1/2 = y

1/20 = y

6 0
1 year ago
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