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BigorU [14]
3 years ago
6

How does the graph of the function h(x)=3x^2 different from the graph of the function f(x)=x?

Mathematics
1 answer:
Tasya [4]3 years ago
5 0
The graph of h(x) = 3x^2 is a curved "bowl" like shape that opens upward. The curve is called a parabola. The two ends go on forever upward. It has symmetry along the y axis. 

In contrast, the graph f(x) = x is a straight line that goes through (0,0) and (1,1). This is known as a linear equation. 
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romanna [79]
3√54-4√24
9√6-4√24
9√6-8√6
√6
6 0
4 years ago
Which statement about graph and horizontal line is true?
Likurg_2 [28]

Answer:

C

Step-by-step explanation:

hi! a horizontal line's slope is always 0.

hope this helps:)

6 0
3 years ago
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Paul worked as a library volunteer for 8 ¼ hours. Harry worked for 3 ½ hours. How much longer did Paul work than Harry?
stiks02 [169]

Answer:

4 3/4

Step-by-step explanation:

= (8 - 3) + (1/4 - 1/2)

= 5 + 1/4 - (1 x 2 over 2 x 2)

= 5 + 1/4 - 2/4

= 5 and (1/2 over 4)

= 5 + -1/4

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8 0
3 years ago
Solve for x ax-bx/x+c = d, if a =/b+d
erica [24]

Answer:

dc/a-b-d

Step-by-step explanation:

ax – bx = d

x + c

Multiply both sides by x + c

ax – bx

(x + c) = d(x + c)

x + c

Simplify

ax – bx

(x+c): ax – bx

x + c

ax – bx = d(x+c)

Expand d(x+c): dx + cd

ax — bx = dx + cd

Subtract dx from both sides

ax – bx – dx = dx + cd – dx

Simplify

ax – bx – dx = cd

Factor ax – bx – dx: x(a – b – d)

x(a - b- d) = cd

Divide both sides by a – b – d; a + b + d

x(a – b - d) cd

a + b + d

a - b - d

a – b-d

Simplify

X =dc/a-b-d

7 0
3 years ago
The temperature in Quebec City was 5°C at 4 pm. By midnight, the temperature dropped 15 degrees.
TEA [102]

Answer:

Point A.

Step-by-step explanation:

We know that the temperature dropped 15 degrees, and that it was initially of 5°C. So, by midnight, the temperature will be of -10°C (5-15=-10).

We also know that the distance between points is of 5°C. So, the point that we have to mark is point A, which represents -10°C.

7 0
3 years ago
Read 2 more answers
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