To solve these type of problems you need to use the pythagoras theorem ⇨ Hypotenuse² = Base² + Altitude².
Here,
- Altitude = 1.6 cm.
- Base = 1.2 cm
- Hypotenuse = x
Now, let's solve for x.
Hypotenuse² = Base² + Altitude²
x² = (1.2)² + (1.6)²
x² = 1.44 + 2.56
x² = 4
x = √4
x = <em><u>2</u></em><em><u>.</u></em>
- So, the value of x is <em><u>2</u><u> </u><u>cm.</u></em>
<h3>
<u>NOTE</u><u> </u><u>:</u><u>-</u></h3>
- Pythagoras theorem can be used only in the cases of right-angled triangles. Here, it's given that the triangle is right angled so we can use this theorem.
- To solve the squares if decimals, take them as whole numbers & then just add the decimal points. For example, ⇨ for (1.2)², take it as 12² , then multiply 12 by 12, you'll get 144. Now, add the decimal place accordingly ⇨ 1.44 . So, (1.2)² = 1.44.
Answer:
78
Step-by-step explanation:
The weight of one box is:
468 ÷ 6 = 78
25 - 13 = 12
12 / 25 = 0.48
the answer is either 12 over 25 or, 0.48
Answer:
Step-by-step explanation:
<u>Answer</u>
4.71 cm²
<u>Explanation</u>
Area of a circle = πr²
Where r is the radius of the circle.
For a sector which is part of a circle, its area is given by;
Area of a sector = (Ф/360)πr²
where Ф is the angle making the sector at the center of the circle.
∴ Area of a sector = (Ф/360)πr²
= 60/360 × π × 3²
= 1/6 × π × 9
= 4.71 cm²