d = distance between the two point charges = 60 cm = 0.60 m
r = distance of the location of point "a" where the electric field is zero from charge 
between the two charges.
= magnitude of charge on one charge
= magnitude of charge on other charge
= 3
= Electric field by charge at point "a"
= Electric field by charge at point "a"
Electric field by charge at point "a" is given as
= k /r²
Electric field by charge at point "a" is given as
= k /(d-r)²
For the electric field to be zero at point "a"
=
k /(d-r)² = k /r²
/(d-r)² = 3 /r²
1/(0.60 - r)² = 3 /r²
r = 0.38 m
r = 38 cm
Explanation:
Let us assume that the separation of plate be equal to d and the area of plates is 
. As the capacitance of capacitor is given as follows.
C = 
It is known that the dielectric strength of air is as follows.
E = 
Expression for maximum potential difference is that the capacitor can with stand is as follows.
dV = E × d
And, maximum charge that can be placed on the capacitor is as follows.
Q = CV
= 
= 
= 
= 
or, = 10.62 nC
Thus, we can conclude that charge on capacitor is 10.62 nC.
Answer:
By using Pythagoras Formula
Explanation:
Measure the distance man is sliding. “It will be c”
Measure the distance of between the tower and a post with which wire is attached. It will be “b”
Then apply Pythagoras Formula c2=a2 + b2 and solve it.
It will give the height of tower.
Answer:
1.9
Explanation:
Efficiency=mechanical advantage/velocity ratio×100
95=M.A/2×100
95=50M.A
M.A=95/50=1.9
