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kumpel [21]
3 years ago
9

Two technicians are discussing fuse testing. Technician A says that a test light should light on both test points of the fuse if

it OK. Technician B says that the fuse is defective if a test light only lights on one side of the fuse. Which technician is correct?a) technician A onlyb) technician B onlyc) both technicians A and Bd) neither technician A nor B
Physics
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

C. Both technicians A and B

Explanation:

Both technicians are absolutely correct because a functional test light is meant to light on both test point if the fuse is working fine which implies that, if the test light doesn't light on both sides then there must be a fault with the fuse. So, both technicians A and B are very correct.

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Which property best makes radio waves safe for diagnosing illnesses through magnetic resonance imaging?
aleksandrvk [35]

Answer:

It is used in MRI because it does not damage cells

Radio waves are used for space research because they have very long wavelengths

Explanation:

Many parts of the electromagnetic spectrum are applied in clinical diagnosis and treatment of illnesses. However, these highly ionizing radiation damage cells and its dosage must be carefully managed to avoid creating radiation related health problems for the patients.

Radio waves can be used in MRI without issues because the energy of the radiation is not sufficient to cause damage to cells but is sufficient to provide images for the sake of medical diagnosis.

Secondly, radio waves have long wavelength. This property is suitable for long range

communication. Hence it can be used in space research

4 0
3 years ago
Read 2 more answers
A 25 kg bear slides, from rest, 12 m down a lodgepole pine tree, moving with a speed of 5.6 m/s just before hitting the ground.
Anuta_ua [19.1K]

Answer:

(A) -2940 J

(B) 392 J

(C) 212.33 N

Explanation:

mass of bear (m) = 25 kg

height of the pole (h) = 12 m

speed (v) = 5.6 m/s

acceleration due to gravity (g) = 9.8 m/s

(A) change in gravitational potential energy (ΔU) = mg(height at the bottom- height at the top)

height at the bottom = 0

         = 25 x 9.8 x (0-12) = -2940 J

(B) kinetic energy of the Bear (KE) = 0.5mv^{2}

           = 0.5 x 25 x 5.6^{2}  = 392 J

(C) average frictional force = \frac{change in thermal energy}{height} = \frac{-(ΔKE+ΔU)}{h}

  • change in KE (ΔKE) = initial KE - final KE
  • ΔKE = 0.5mv^{2} - 0.5mvf^{2}            
  • when the Bear reaches the bottom of the pole, the final velocity (Vf) is 0, therefore the change in kinetic energy becomes  ΔKE = 0.5x25x5.6^{2} - 0 = 392 J

 \frac{-(ΔKE+ΔU)}{h}[/tex] = \frac{-(392 + (-2940))}{12}

=  \frac{(-392 + 2940)}{12} = 212.33 N

5 0
3 years ago
What is noble gases<br>​
Marysya12 [62]

Answer:

helium, neon, argon,krypton, xenon, and radonoccupying Group 0 (18) of the periodic table. They were long believed to be totally unreactive but compounds of xenon, krypton, and radon are now known.

6 0
3 years ago
In a laboratory, you determine that the density of a certain solid is 5.23× 10 −6 kg/m m 3 . convert this density into kilograms
tamaranim1 [39]

Density is given as

\rho = 5.23 * 10^{-6} kg/mm^3

now we have to convert this density into kg/m^3

now we have

1 m = 1000 mm

\rho = 5.23 * 10^{-6} \frac{kg}{(1*10^-3 m)^3}

\rho = 5.23 * 10^{-6} \frac{1*10^9 kg}{m^3}

\rho = 5.23 * 10^3 kg/m^3

\rho = 5230 kg/m^3

8 0
4 years ago
Explain why models are often used to study other planets ?
bonufazy [111]
The models are used to represent what you are studying in this case would be a planet. A model of Saturn and its rings and the moons surrounding it would be fantastic to look at when you have no way of going there
7 0
3 years ago
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