1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kumpel [21]
3 years ago
9

Two technicians are discussing fuse testing. Technician A says that a test light should light on both test points of the fuse if

it OK. Technician B says that the fuse is defective if a test light only lights on one side of the fuse. Which technician is correct?a) technician A onlyb) technician B onlyc) both technicians A and Bd) neither technician A nor B
Physics
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

C. Both technicians A and B

Explanation:

Both technicians are absolutely correct because a functional test light is meant to light on both test point if the fuse is working fine which implies that, if the test light doesn't light on both sides then there must be a fault with the fuse. So, both technicians A and B are very correct.

You might be interested in
Analisis morfologico palabra yo gane el primer premio
ale4655 [162]

Answer:

eres raro jajaja pero eres realmente genial y ordenado espero que esto te ayude jajaja

Explanation:

5 0
3 years ago
A street light is at the top of a 19 foot tall pole. A woman 5.25 feet tall walks towards the pole with a speed of 7ft/sec along
bezimeni [28]
Answer:

The tip of her shadow is moving at the speed of 9.66 ft/sec

Explanation:

The height of the street light = 19 feet

The height of the woman = 5.25 feet

Distance between the woman and the base of the pole, x = 35 ft

The speed of the woman towards the pole, dx/dt = 7ft/sec

The distance from the base of the streetlight to the tip of the woman's shadow = y

The distance from the woman to the tip of her shadow = y - x

The diagram illustrating this description is shown below

Using similar triangle:

\begin{gathered} \frac{19}{5.25}=\text{ }\frac{y}{y-x} \\ 19(y-x)\text{ = 5.25y} \\ 19y-19x\text{ = 5.25y} \\ 19y-5.25y\text{ = 19x} \\ 13.75y\text{ = 19x} \\ y\text{ = }\frac{19}{13.75}x \\ y\text{ = }1.38x \end{gathered}

Find the derivative of both sides with respect to time, t

\begin{gathered} \frac{dy}{dt}=\text{ 1.38}\frac{dx}{dt} \\ \frac{dy}{dt}=\text{ 1.38(7)} \\ \frac{dy}{dt}\text{ = }9.66\text{ ft/sec} \end{gathered}

The tip of her shadow is moving at the speed of 9.66 ft/sec

7 0
1 year ago
If something is traveling at a constant velocity are forces balanced or unbalanced?
lubasha [3.4K]

Answer:

If something is traveling at a constant velocity, then forces are balanced.

Explanation:

If something is traveling at a constant velocity, then the forces must be balanced because a constant velocity is only achieved with balanced forces.

<em>Please </em><em>like </em><em>and </em><em>mark </em><em>brainliest</em><em>!</em><em> </em>

<em>Hope </em><em>it </em><em>helps!</em>

7 0
3 years ago
Read 2 more answers
Calculate the potential V(r) for r&gt;rb. (Hint: The net potential is the sum of the potentials due to the individual spheres.)
Marat540 [252]

Answer:

The potential for r > rb is equal to zero.

Explanation:

For r > rb, the potential is:

V=\frac{Kq}{r}

Then, the net potential is:

V_{(r)} =\frac{K(+\epsilon )}{r} +\frac{K(-\epsilon )}{r}

K=\frac{1}{4\pi \epsilon _{o}  }

V_{(r)} =\frac{K(+\epsilon )}{r} -\frac{K(\epsilon )}{r}\\V_{(r)}=0

8 0
4 years ago
A series RL circuit includes a 6.05 V 6.05 V battery, a resistance of R = 0.655 Ω , R=0.655 Ω, and an inductance of L = 2.55 H.
Ivenika [448]

Answer:

The induced emf 1.43 s after the circuit is closed is 4.19 V

Explanation:

The current equation in LR circuit is :

I=\frac{V}{R} (1-e^{\frac{-Rt}{L} })    .....(1)

Here I is current, V is source voltage, R is resistance, L is inductance and t is time.

The induced emf is determine by the equation :

V_{e}=L\frac{dI}{dt}

Differentiating equation (1) with respect to time and put in above equation.

V_{e}= L\times\frac{V}{R}\times\frac{R}{L}e^{\frac{-Rt}{L} }

V_{e}=Ve^{\frac{-Rt}{L} }

Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.

V_{e}=6.05e^{\frac{-0.655\times1.43}{2.55} }

V_{e}=4.19\ V

5 0
3 years ago
Other questions:
  • What combines to form bonds in compounds?A.atoms of elementsB.moleculesC.types of mineralsD.valences
    11·2 answers
  • Question 5 (1 point)
    6·1 answer
  • The curvature of the helix r​(t)equals(a cosine t )iplus(a sine t )jplusbt k​ (a,bgreater than or equals​0) is kappaequalsStartF
    8·1 answer
  • As altitude increases, air pressure ____.
    7·1 answer
  • Heredity, age, sex, exercise habits, diet, and lifestyle all play a part in determining our ______
    11·1 answer
  • Identify and describe one past geologic process that formed copper ore deposits.
    10·1 answer
  • A mother and daughter are playing catch, as seen in the image below. At which point
    13·1 answer
  • Ocean zones can be classified based on distance from Shore into intertidal,
    9·2 answers
  • What would the net force be on the box in the problems shown below.( both force and direction).​
    7·1 answer
  • David is running laps around his apartment complex. Each lap is 1000 m. Starting from his front door and ending at his front doo
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!