A ramp is 1.0 m high and 3.0 m long. What is the IMA of the ramp?
1 answer:
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This question is incomplete, the complete question is;
Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant speed of 72 km/h. The x-y axes are attached to car B. The distance separating the two cars at the instant depicted is 40 m. Determine: the angular velocity of Bxy rotating frame (ω).
Answer:
the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s
Explanation:
Given the data in the question and image below and as illustrated in the second image;
distance S = 40 m
V = 54 km/hr
V = 72 km/hr
α = 100 m
now, angular velocity of Bxy will be;
ω = V
/ α
so, we substitute
ω = ( 54 × 1000/3600) / 100
ω = 15 / 100
ω = 0.15 rad/s
Therefore, the angular velocity of Bxy rotating frame (ω) is 0.15 rad/s
Answer:
The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.
Explanation:
Given that,
Initial velocity u= 128 ft/sec
Equation of height
....(I)
(a). We need to calculate the maximum height
Firstly we need to calculate the time
From equation (I)
Now, for maximum height
Put the value of t in equation (I)
(b). The number of seconds it takes the object to hit the ground.
We know that, when the object reaches ground the height becomes zero
Hence, The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.