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1 year ago

What are some shared properties of both transition metals and alkali metals.

1 answer:

7 0

Both transition metals and alkali metals are good conductors of heat and electricity, react with water, and are easily oxidized.

<h3>What are alkali metals and transition metals?</h3>

The alkali metals are elements of group 1 which are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (Fr). They are also known as the s-block elements because they have their outermost electron in an s-orbital.

The alkali metals are shiny, soft, highly reactive metals and readily lose their outermost electron to create cations with charge +1. They can tarnish rapidly in the air due to oxidation by atmospheric moisture and oxygen.

Transition elements or transition metals are elements that have partially filled d-orbitals. An element having a d-subshell that is partially filled with electrons or can form stable cations with an incompletely filled d orbital.

Any element present in the d-block of the modern periodic table which consists of groups 3 to 12, is considered to be a transition element. For example, the mercury in the +2 oxidation state, corresponds to an electronic configuration of (n-1)d¹⁰. Many paramagnetic compounds are formed by transition metals because they have unpaired electrons in the d orbital.

Learn more about transition metals and alkali metals, here:

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How does heat affect a water droplet's state of matter

Olegator [25]

Answer:

Explanation:

A substance with a high specific heat, such as the water in Figure 9, heats up and cools down slowly because a much larger quantity of heat is required to cause its temperature to rise or fall by the same amount. Matter can change from one state to another when thermal energy is absorbed or released.

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4 years ago

The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of

taurus [48]

Answer:

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

where m is mass and c, the specific heat of the substance

27.4 J / (80°C - 50°C) = c . 6.2 g

[27.4 J / (80°C - 50°C)] / 6.2 g = c

27.4 J / 30°C . 1/6.2g = c

0.147 J/g°C = c

Therefore, the heat capacity is 0.913 J/°C

7 0

3 years ago

How many kilograms of oxygen did Samantha need to utilize to react with 36.29 kg of triglycerides (C55H104O6)?

Paraphin [41]

Answer:

105.33Kg of O2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

C55H104O6 + 78O2 —> 55CO2 + 52H2O

Step 2:

Determination of the masses of C55H104O6 and O2 that reacted from the balanced equation.

This is illustrated below:

Molar mass of C55H104O6 = (12x55) + (104x1) + (16x6) = 860g/mol

Mass of C55H104O6 from the balanced equation = 1 x 860 = 860g.

Divide the mass of C55H104O6 by 1000 to express in kg i.e

Mass of C55H104O6 = 860/1000= 0.86Kg

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 78 x 32 = 2496g.

Divide the mass of O2 by 1000 to express in kg i.e

Mass of O2 = 2496/1000 = 2.496kg.

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Step 3:

Determination of the mass of O2 in kg needed to react with 36.29 kg of triglycerides (C55H104O6).

This can be obtained as follow:

From the balanced equation above,

0.86kg of C55H104O6 reacted with 2.496Kg of O2.

Therefore, 36.29 kg of C55H104O6 will react with = (36.29 x 2.496)/0.86 = 105.33Kg of O2.

Therefore, 105.33Kg of O2 is needed for the reaction.

5 0

3 years ago

A. 207 kJ<br> B. 4730 kJ<br> C. 9460 kJ<br> D. 414 kJ

Leno4ka [110]

Answer:

$\boxed {\boxed {\sf C. \ 9460 \ kJ}}$

Explanation:

The formula we must use is given to us:

$q=mL_{vapor}$

q is the energy, m is the mass, and L(vapor) is the latent heat of vaporization.

The energy is what we calculate and the mass is 2 kilograms. We need to find the latent heat of vaporization, which is on the table.

We know the sample is copper.
Find that element on the table, then the third box tells us it's latent heat of vaporization is 4730 kJ/kg

Now we know:

$m= 2 \ kg \\L_{vapor}=4730 \ kJ/kg$

Substitute the values into the formula.

$q=(2 \ kg ) * (4730 \ kJ/kg)$

Multiply. Note that the kilograms (kg) will cancel each other out.

$q= 2* 4730 \ kJ$

$q= 9460 \ kJ$

<u>9460 kilojoules</u> are required to vaporize 2 kilograms of copper.

3 0

3 years ago

How many more atoms are there in 48g of C compared with 48.6g of Mg? Explain your answer.

balu736 [363]

Answer:

The number of carbon atoms is twice the number of magnesium atoms

6 0

2 years ago