Answer:

Explanation:
Hello there!
In this case, according to the given information and chemical equation, it turns out possible for us to calculate the moles of C2O4^2- by firstly setting up the equilibrium expression:
![Kc=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[Fe^{3+}][C_2O_4^{2-}]^3}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5B%5BFe%28C_2O_4%29_3%5D%5E%7B3-%7D%5D%7D%7B%5BFe%5E%7B3%2B%7D%5D%5BC_2O_4%5E%7B2-%7D%5D%5E3%7D)
However, according to the question, we just need to apply the given 1:3 mole ratio in the chemical reaction, of iron (III) ions to oxalate ions to obtain:

Regards!
Lithium has the lowest. if fluorine is the highest then lithium is the lowest. i hope this helps you out!
Answer:
he hates it he loves it im only doin this for points
Answer: There is one way to write it but i’ll also provide an unbalanced equation and a balanced one.
Explanation:
Unbalanced : Ba (aq) + Cl2 (aq)—-> BaCl (aq)
Balanced : 2Ba (aq) + Cl2 (aq)—> 2BaCl(aq)