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Alisiya [41]
3 years ago
13

The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of

this sample?
Chemistry
1 answer:
taurus [48]3 years ago
7 0

Answer:

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

where m is mass and c, the specific heat of the substance

27.4 J / (80°C - 50°C) = c . 6.2 g

[27.4 J / (80°C - 50°C)] / 6.2 g = c

27.4 J / 30°C . 1/6.2g = c

0.147 J/g°C = c

Therefore, the heat capacity is 0.913 J/°C

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A nuclide of phosphorus 3015P decays into a nuclide of silicon 3014Si. In order to satisfy charge conservation and lepton number
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<h3>What is conservation of mass?</h3>

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